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Flura [38]
3 years ago
11

Ammonium perchlorate NH4ClO4 is a powerful solid rocket fuel, used in the Space Shuttle boosters. It decomposes into nitrogen N2

gas, chlorine Cl2 gas, oxygen O2 gas and water vapor, releasing a great deal of energy. Calculate the moles of oxygen produced by the reaction of 0.055mol of ammonium perchlorate. Be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant digits.
Chemistry
1 answer:
patriot [66]3 years ago
7 0

Answer: 0.055 moles of O_2 are produced by the reaction of 0.055 mol of ammonium perchlorate.

Explanation:

The balanced chemical reaction for decomposition of ammonium perchlorate is:

2NH_4ClO_4\rightarrow N_2+Cl_2+2O_2+4H_2O  

According to stoichiometry :

2 moles of NH_4ClO_4 produce = 2 moles of O_2

Thus 0.055 moles of NH_4ClO_4 will produce =\frac{2}{2}\times 0.055=0.055moles of O_2

Thus 0.055 moles of O_2 are produced by the reaction of 0.055mol of ammonium perchlorate.

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zlopas [31]
<h3>Answer:</h3>

1.83 × 10⁻⁷ mol Au

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

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<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.60 × 10⁻⁵ g Au (Gold)

<u>Step 2: Identify Conversions</u>

Molar Mass of Au - 196.97 g/mol

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 3.60 \cdot 10^{-5} \ g \ Au(\frac{1 \ mol \ Au}{196.97 \ g \ Au})
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<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1.82769 × 10⁻⁷ mol Au ≈ 1.83 × 10⁻⁷ mol Au

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