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FromTheMoon [43]
3 years ago
4

A 9-cm-diameter spherical ball whose surface is main­tained at a temperature of 110°C is suspended in the middle of a room at 20

°C. If the convection heat transfer coefficient is 15 W/m2·°C and the emissivity of the surface is 0.8, determine the total rate of heat transfer from the ball.

Engineering
1 answer:
son4ous [18]3 years ago
4 0

Answer:

the total rate of heat transfer from the ball = 50.59W

Explanation:

The application of heat transfer by convection and radiation was used to solve the question. For heat transfer by radiation involves the emissivity and the stefan boltzmaan constant, for heat transfer by convection involves the area and the heat transfer coefficient. The addition of both heat transfer in both medium is used to calculate the total heat transfer from the ball.

The steps is as shown in the attachment.

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A device that helps increase field worker productivity by providing reliable location and time
frutty [35]

Global Positioning System (GPS) is the device that helps increase field worker productivity by providing reliable location and time.

<u>Explanation:</u>

GPS, a satellite based and radio navigation oriented system. It can be accessible from anywhere in the world irrespective of obstructions in weather and extremely used by Air force.

With advancing technologies, the uses of GPS can be extended to improve the productivity of the workforce by identifying location services and field operation insights.

Today, GPS chips are built in various devices including smartphones, tablet, and other gadgets. It doe not need users to send data as it can work on internet reception.

3 0
4 years ago
Air exits a compressor operating at steady-state, steady-flow conditions at 150 oC, 825 kPa, with a velocity of 10 m/s through a
ioda

Answer:

a) Qe = 0.01963 m^3 / s , mass flow rate m^ = 0.1334 kg/s

b) Inlet cross sectional area = Ai = 0.11217 m^2 , Qi = 0.11217 m^3 / s    

Explanation:

Given:-

- The compressor exit conditions are given as follows:

                  Pressure ( Pe ) = 825 KPa

                  Temperature ( Te ) = 150°C

                  Velocity ( Ve ) = 10 m/s

                  Diameter ( de ) = 5.0 cm

Solution:-

- Define inlet parameters:

                  Pressure = Pi = 100 KPa

                  Temperature = Ti = 20.0

                  Velocity = Vi = 1.0 m/s

                  Area = Ai

- From definition the volumetric flow rate at outlet ( Qe ) is determined by the following equation:

                   Qe = Ae*Ve

Where,

           Ae: The exit cross sectional area

                   Ae = π*de^2 / 4

Therefore,

                  Qe = Ve*π*de^2 / 4

                  Qe = 10*π*0.05^2 / 4

                  Qe = 0.01963 m^3 / s

 

- To determine the mass flow rate ( m^ ) through the compressor we need to determine the density of air at exit using exit conditions.

- We will assume air to be an ideal gas. Thus using the ideal gas state equation we have:

                   Pe / ρe = R*Te  

Where,

           Te: The absolute temperature at exit

           ρe: The density of air at exit

           R: the specific gas constant for air = 0.287 KJ /kg.K

             

                ρe = Pe / (R*Te)

                ρe = 825 / (0.287*( 273 + 150 ) )

                ρe = 6.79566 kg/m^3

- The mass flow rate ( m^ ) is given:

               m^ = ρe*Qe

                     = ( 6.79566 )*( 0.01963 )

                     = 0.1334 kg/s

- We will use the "continuity equation " for steady state flow inside the compressor i.e mass flow rate remains constant:

              m^ = ρe*Ae*Ve = ρi*Ai*Vi

- Density of air at inlet using inlet conditions. Again, using the ideal gas state equation:

               Pi / ρi = R*Ti  

Where,

           Ti: The absolute temperature at inlet

           ρi: The density of air at inlet

           R: the specific gas constant for air = 0.287 KJ /kg.K

             

                ρi = Pi / (R*Ti)

                ρi = 100 / (0.287*( 273 + 20 ) )

                ρi = 1.18918 kg/m^3

Using continuity expression:

               Ai = m^ / ρi*Vi

               Ai = 0.1334 / 1.18918*1

               Ai = 0.11217 m^2          

- From definition the volumetric flow rate at inlet ( Qi ) is determined by the following equation:

                   Qi = Ai*Vi

Where,

           Ai: The inlet cross sectional area

                  Qi = 0.11217*1

                  Qi = 0.11217 m^3 / s    

- The equations that will help us with required plots are:

Inlet cross section area ( Ai )

                Ai = m^ / ρi*Vi  

                Ai = 0.1334 / 1.18918*Vi

                Ai ( V ) = 0.11217 / Vi   .... Eq 1

Inlet flow rate ( Qi ):

                Qi = 0.11217 m^3 / s ... constant  Eq 2

               

6 0
3 years ago
Is a steam power plant a heat engine?
Novosadov [1.4K]

Answer:

Yes

Explanation:

Yes steam power plant is heat engine.

As we know that a heat engine takes from source heat and produce some amount of work and reject the heat to the sink.

So the steam power plant fulfill the all requirement like it take heat from boiler and produce some amount work and then reject the heat by using condenser.So we can say that steam power plant is an example of heat engine.

7 0
4 years ago
The acceleration due to gravity at sea level is g=9.81 m/s^2. The radius of the earth is 6370 km. The universal gravitational co
solmaris [256]

Answer:

Mass of earth will be M=5.96\times 10^{24}kg

Explanation:

We have given acceleration due to gravity g=9.81m/sec^2

Radius of earth = 6370 km =6370\times 10^3m

Gravitational constant G=6.67\times 10^{-11}Nm^2/kg^2

We know that acceleration due to gravity is given by

g=\frac{GM}{R^2}, here G is gravitational constant, M is mass of earth and R is radius of earth

So 9.81=\frac{6.67\times 10^{-11}\times M}{(6370\times 10^3)^2}

M=5.96\times 10^{24}kg

So mass of earth will be M=5.96\times 10^{24}kg

3 0
3 years ago
Risks are Not Perceived Differently from What is Happening<br> False<br> True
Gnoma [55]

Answer:

False......................

8 0
3 years ago
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