1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
stira [4]
3 years ago
12

Air exits a compressor operating at steady-state, steady-flow conditions at 150 oC, 825 kPa, with a velocity of 10 m/s through a

circular pipe of 5.0 cm diameter.
a. Determine the outlet volumetric flow rate and the mass flow rate of the air.
b. If the air enters the compressor through an inlet at 20.0 oC and 100 kPa and a velocity of 1.0 m/s, determine the volumetric flow rate of the air entering the compressor and the required cross-sectional area of the inlet.
c. Using your equations, plot the inlet volumetric flow rate and the inlet cross-sectional area as the inlet air velocity varies between 0.25 m/s and 10.0 m/s.
Engineering
1 answer:
ioda3 years ago
6 0

Answer:

a) Qe = 0.01963 m^3 / s , mass flow rate m^ = 0.1334 kg/s

b) Inlet cross sectional area = Ai = 0.11217 m^2 , Qi = 0.11217 m^3 / s    

Explanation:

Given:-

- The compressor exit conditions are given as follows:

                  Pressure ( Pe ) = 825 KPa

                  Temperature ( Te ) = 150°C

                  Velocity ( Ve ) = 10 m/s

                  Diameter ( de ) = 5.0 cm

Solution:-

- Define inlet parameters:

                  Pressure = Pi = 100 KPa

                  Temperature = Ti = 20.0

                  Velocity = Vi = 1.0 m/s

                  Area = Ai

- From definition the volumetric flow rate at outlet ( Qe ) is determined by the following equation:

                   Qe = Ae*Ve

Where,

           Ae: The exit cross sectional area

                   Ae = π*de^2 / 4

Therefore,

                  Qe = Ve*π*de^2 / 4

                  Qe = 10*π*0.05^2 / 4

                  Qe = 0.01963 m^3 / s

 

- To determine the mass flow rate ( m^ ) through the compressor we need to determine the density of air at exit using exit conditions.

- We will assume air to be an ideal gas. Thus using the ideal gas state equation we have:

                   Pe / ρe = R*Te  

Where,

           Te: The absolute temperature at exit

           ρe: The density of air at exit

           R: the specific gas constant for air = 0.287 KJ /kg.K

             

                ρe = Pe / (R*Te)

                ρe = 825 / (0.287*( 273 + 150 ) )

                ρe = 6.79566 kg/m^3

- The mass flow rate ( m^ ) is given:

               m^ = ρe*Qe

                     = ( 6.79566 )*( 0.01963 )

                     = 0.1334 kg/s

- We will use the "continuity equation " for steady state flow inside the compressor i.e mass flow rate remains constant:

              m^ = ρe*Ae*Ve = ρi*Ai*Vi

- Density of air at inlet using inlet conditions. Again, using the ideal gas state equation:

               Pi / ρi = R*Ti  

Where,

           Ti: The absolute temperature at inlet

           ρi: The density of air at inlet

           R: the specific gas constant for air = 0.287 KJ /kg.K

             

                ρi = Pi / (R*Ti)

                ρi = 100 / (0.287*( 273 + 20 ) )

                ρi = 1.18918 kg/m^3

Using continuity expression:

               Ai = m^ / ρi*Vi

               Ai = 0.1334 / 1.18918*1

               Ai = 0.11217 m^2          

- From definition the volumetric flow rate at inlet ( Qi ) is determined by the following equation:

                   Qi = Ai*Vi

Where,

           Ai: The inlet cross sectional area

                  Qi = 0.11217*1

                  Qi = 0.11217 m^3 / s    

- The equations that will help us with required plots are:

Inlet cross section area ( Ai )

                Ai = m^ / ρi*Vi  

                Ai = 0.1334 / 1.18918*Vi

                Ai ( V ) = 0.11217 / Vi   .... Eq 1

Inlet flow rate ( Qi ):

                Qi = 0.11217 m^3 / s ... constant  Eq 2

               

You might be interested in
joe is an exceptional systems engineer who hopes to work at the techtonic group. he is handicapped and uses a wheelchair. techto
ASHA 777 [7]

The HR department should install wheelchair ramps and widen the doorways as they don't want to loose an exceptional systems engineer who hopes to work at the techtonic group.

What is a wheelchair ramps?

A wheelchair ramp is an inclined plane that can be installed in addition to or instead of stairs. Ramps make it easier for wheelchair users, as well as people pushing strollers, carts, or other wheeled objects, to enter a building.

The Americans with Disabilities Act requires wheelchair ramps (or other ways for wheelchair users to access a building, such as a wheelchair lift) in new construction for public accommodations in the United States.

A wheelchair ramp can be fixed, semi-fixed, or portable. Permanent ramps are intended to be bolted or otherwise attached to the ground. Semi-permanent ramps are commonly used in the short term and rest on top of the ground or concrete pad.

To know more about wheelchair ramps, visit: brainly.com/question/17395685

#SPJ4

5 0
1 year ago
A packet weighs 40kg in air but when it is totally submerged into a 1mx1m square tank the weight of the packet is only 18kg. How
Irina18 [472]

Answer:

water  rise = 22 mm

Explanation:

weight of packet IN AIR = 40 *9.81 =392.4 N

weight of packet  IN WATER= 18 *9.81 =176.58 N

by Archimedi's principle

difference in weight = weight of displaced water

w_a - w_w = \rho_w v_d g

392.4 - 176.58 = 1000* v_d* 9.81

v_d = 0.022 m^3

v_d = A*H_rise

0.022 =1*H_rise

H_rise = 0.022 m = 22 mm

water  rise = 22 mm

5 0
3 years ago
What are the complex structures and the advantages and disadvantages
Svetllana [295]

Answer:

A complex system is a system composed of many components which may interact with each other.

ADVANTAGES

Structs are marginally faster at runtime than classes, due to optimisations done by the compiler. You can enforce full immutability. If you declare a struct instance as let, you will not be able to change its properties.

DISADVANTAGES

A complex corporate structure makes communication more difficult. For instance, when workers must interact with several supervisors, the various directives might work at cross purposes. Also, messages might get lost in the shuffle if there is no simple way to communicate within the organization.

4 0
3 years ago
5.11: Population Write a program that will predict the size of a population of organisms. The program should ask the user for th
fomenos

Answer:

// using c++ language

#include "stdafx.h";

#include <iostream>

#include<cmath>

using namespace std;

//start

int main()

{

  //Declaration of variables in the program

  double start_organisms;

  double daily_increase;

  int days;

  double updated_organisms;

  //The user enters the number of organisms as desired

  cout << "Enter the starting number of organisms: ";

  cin >> start_organisms;

  //Validating input data

  while (start_organisms < 2)

  {

      cout << "The starting number of organisms must be at least 2.\n";

      cout << "Enter the starting number of organisms: ";

      cin >> start_organisms;

  }

  //The user enters daily input, here's where we apply the 5.2% given in question

  cout << "Enter the daily population increase: ";

  cin>> daily_increase;

  //Validating the increase

  while (daily_increase < 0)

  {

      cout << "The average daily population increase must be a positive value.\n ";

      cout << "Enter the daily population increase: ";

      cin >> daily_increase;

  }

  //The user enters number of days

  cout << "Enter the number of days: ";

  cin >> days;

  //Validating the number of days

  while (days<1)

  {

      cout << "The number of days must be at least 1.\n";

      cout << "Enter the number of days: ";

      cin >> days;

  }

 

  //Final calculation and display of results based on formulas

  for (int i = 0; i < days; i++)

  {

      updated_organisms = start_organisms + (daily_increase*start_organisms);

      cout << "On day " << i + 1 << " the population size was " << round(updated_organisms)<<"."<<"\n";

     

      start_organisms = updated_organisms;

  }

  system("pause");

   return 0;

//end

}

4 0
3 years ago
Take my points already been warned once
ANTONII [103]

Answer:

bet

Explanation:

give me em

5 0
3 years ago
Read 2 more answers
Other questions:
  • La extensión de un resumen debe estar en un rango de _________ del texto inicial. a)25 a 35 % b)10 a 20 % c)15 a 20 % d)20 a 25
    9·1 answer
  • Air is compressed in the compressor of a turbojet engine. Air enters the compressor at 270 K and 58 kPa and exits the compressor
    13·1 answer
  • Find the largest number. The process of finding the maximum value (i.e., the largest of a group of values) is used frequently in
    6·1 answer
  • When it comes to making a good impression in a work setting, it does not apply to an initial contact, since both people are meet
    9·1 answer
  • The dot plot shows the number of cupcakes bought by each person who came to a bake sale.
    15·1 answer
  • A motor cycle is moving up an incline of 1 in 30 at a speed of 80 km/h,and then suddenly the engine shuts down.The tractive resi
    11·1 answer
  • Identify the different engineering activities/steps in the engineering design process for each steps,summarize in 1–3 sentences
    13·1 answer
  • Which of the following activities could be considered unethical?
    7·1 answer
  • Which Two moon phases are directly opposite each other?
    9·2 answers
  • Please help me. I have no idea what I'm doing.​
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!