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disa [49]
3 years ago
11

The atom in a chemical bond that attracts electrons more strongly acquires a(n)____________ charge, and the other atom acquires

a(n)__________ charge. If the electron transfer is significant but not enough to form ions, the atoms acquire _____________ and charges. The bond in this situation is called a polar covalent bond.
Chemistry
1 answer:
pshichka [43]3 years ago
4 0

Answer:

The answer to your question is below

Explanation:

The atom in a chemical bond that attracts electrons more strongly acquires a(n)__<u>negative</u>______ charge, and the other atom acquires a(n)_<u>positive</u>_______ charge. If the electron transfer is significant but not enough to form ions, the atoms acquire _<u>dipoles</u>_________ and charges. The bond in this situation is called a polar covalent bond.

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Answer:

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Explanation:

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2 years ago
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If the initial concentration of a is 0.00540 m, what will be the concentration after 795 s?
zavuch27 [327]
<span>Feb 19, 2014 - The units of k tell you that this is a second order reaction. So, to solve this, you need to use the integrated rate law for a 2nd order reaction: 1/[A] = kt + 1/[A]o 1/[A] = 0.540/Ms (835 s) + 1/0.00640 1/[A] = 607 [A] = 1.65X10^-3 M.</span><span>
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7 0
3 years ago
Krypton-79 has a half-life of 35 hours. how many half-lives have passed after 105 hours?
Nookie1986 [14]
The number of half -lives that has passed after 105  hours  for krypton-79 that has  half-life of 35 hours is calculated as below

if 1 half life = 35 hours

what about 105 hours = ? half-lives

= (1 half life  x105  hours) /35 hours = 3 half-lives  has passed after 105 hours
6 0
3 years ago
Acetic acid has a Kb of 2.93 °C/m and a normal boiling point of 118.1 °C. What would be the boiling point of a solution made by
alexdok [17]

Boiling point elevation is given as:

ΔTb=iKbm

Where,

ΔTb=elevation in the boiling point

that is given by expression:

ΔTb=Tb (solution) - Tb (pure solvent)

Here Tb (pure solvent)=118.1 °C

i for CaCO3= 2

Kb=2.93 °C/m

m=Molality of CaCO₃:

Molality of CaCO₃=Number of moles of CaCO₃/ Mass of solvent (Kg)

=(Given Mass of CaCO3/Molar mass of CaCO₃)/ Mass of solvent (Kg)

=(100.0÷100 g/mol)/0.4

= 2.5 m

So now putting value of m, i and Kb in the boiling point elevation equation we get:

ΔTb=iKbm

=2×2.93×2.5

=14.65 °C

boiling point of a solution can be calculated:

ΔTb=Tb (solution) - Tb (pure solvent)

14.65=Tb (solution)-118.1

Tb (solution)=118.1+14.65

=132.75

3 0
3 years ago
Is the bond length in HCl the same as that in DCl? The wavenumbers of the J = 0  1 rotational transitions for H35Cl and 2H35Cl
konstantin123 [22]
I’m sorry i do not know
4 0
3 years ago
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