1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Olenka [21]
3 years ago
6

Acetic acid has a Kb of 2.93 °C/m and a normal boiling point of 118.1 °C. What would be the boiling point of a solution made by

dissolving 100.0 g of CaCO3 in 400.0 g of acetic acid?
Please explain your answer.

Chemistry
1 answer:
alexdok [17]3 years ago
3 0

Boiling point elevation is given as:

ΔTb=iKbm

Where,

ΔTb=elevation in the boiling point

that is given by expression:

ΔTb=Tb (solution) - Tb (pure solvent)

Here Tb (pure solvent)=118.1 °C

i for CaCO3= 2

Kb=2.93 °C/m

m=Molality of CaCO₃:

Molality of CaCO₃=Number of moles of CaCO₃/ Mass of solvent (Kg)

=(Given Mass of CaCO3/Molar mass of CaCO₃)/ Mass of solvent (Kg)

=(100.0÷100 g/mol)/0.4

= 2.5 m

So now putting value of m, i and Kb in the boiling point elevation equation we get:

ΔTb=iKbm

=2×2.93×2.5

=14.65 °C

boiling point of a solution can be calculated:

ΔTb=Tb (solution) - Tb (pure solvent)

14.65=Tb (solution)-118.1

Tb (solution)=118.1+14.65

=132.75

You might be interested in
A 2.4 L balloon holds 3.7 mol He. If 1.6 mol He are added to the balloon, what is the new volume?
Elanso [62]
For this question, lets apply Avagadro's law
when Pressure and temperature are constant, the volume occupied is directly proportional to the number of moles of gases.
\frac{V}{n} = k
where V-volume, n-number of moles and k - constant 
Therefore at 2 instances 
\frac{V1}{n1} =  \frac{V2}{n2}
where V1 and n1 are for 1st instance 
and V2 and n2 are for 2nd instance 
therefore 
\frac{V1}{n1} = \frac{V2}{n2}
V1 = 2.4 L
n1 = 3.7 mol
n2 = 3.7 + 1.6 = 5.3 mol
since more He moles are added at the 2nd instance its the sum of the moles.
V2 needs to be calculated \frac{2.4}{3.7}  = \frac{V2}{5.3}
V2 = 2.4 x 5.3 / 3.7
     = 3.4 L
Answer is 1st option 3.4 L


6 0
3 years ago
The reaction of 60.0 g of aluminum oxide with 30.0 g of carbon produced CO gas and 22.5 g of aluminum metal. What is the percent
natulia [17]

Answer:

The answer to your question is: 70.8%

Explanation:

Data

Al₂O₃ = 60 g

C = 30 g

CO = gas

Al = 22.5 g

MW Al₂O₃ = 102 g

MW C = 12 g

MW Al = 54 g

Reaction

                 Al₂O₃    +     3C     ⇒       3 CO    +    2 Al

Limiting reactant

                            102 g of Al₂O₃  -------------- 54 g Al

                             60 g                 --------------   x

                             x = 31.8 g

                            36 g of C ------------------ 54 g of Al

                            30 g of C ------------------  x

                            x = 45 g of Al

Limiting reactant = Al₂O₃

Percent yield = \frac{22.5}{31.8} x 100

Percent yield = 70.75 %

5 0
2 years ago
A sample of gas initially has a volume of 1.42 L at 293 K and 1.30 atm. What volume will the sample have if the pressure changes
worty [1.4K]

Answer:

1.35

Explanation:

5 0
2 years ago
Please help! I really don’t understand it
chubhunter [2.5K]

Answer:

C. It makes sure there is a balance inside the body

Explanation:

Hope this helps

7 0
2 years ago
Read 2 more answers
The density of silver is 10.5 g/cm3. What is the mass (in kilograms) of a cube of silver that measures 0.94 m on each side?
Rzqust [24]

Answer:

8721.132 Kg.

Explanation:

The following data were obtained from the question:

Density (D) of silver = 10.5 g/cm³

Length (L) of silver = 0.94 m

Mass (m) of silver =.?

Next, we shall determine the volume of silver. This can be obtained as follow:

Volume = Length × Length × Length

Volume = L × L × L

Volume = L³

Length (L) of silver = 0.94 m

Volume (V) of silver =?

Volume (V) of silver = 0.94³

Volume (V) of silver = 0.830584 m³

Next, we shall convert 0.830584 m³ to cm³. This can be obtained as follow:

1 m³ = 1×10⁶ cm³

Therefore,

0.830584 m³ = 0.830584 m³ / 1 m³ × 1×10⁶ cm³

0.830584 m³ = 830584 cm³

Therefore, 0.830584 m³ is equivalent 830584 cm³.

Thus, the volume of the silver is 830584 cm³.

Next, we shall determine the mass of the silver. This can be obtained as follow:

Density (D) of silver = 10.5 g/cm³

Volume of the silver = 830584 cm³.

Mass of silver =.?

Density = mass /

10.5 = mass of silver /830584

Cross multiply

Mass of silver = 10.5 × 830584

Mass of silver = 8721132 g

Finally, we shall convert the mass of silver, 8721132 g to kilogram (kg). This can be obtained as follow:

1000 g = 1 Kg

Therefore,

8721132 g = 8721132 g / 1000 g × 1 Kg

8721132 g = 8721.132 Kg

Therefore, the mass of each cube of silver is 8721.132 Kg

3 0
3 years ago
Other questions:
  • An iron nail with a mass of 12 g absorbs 12 J of heat.
    5·1 answer
  • I'll give brainliest to the best answer!!
    11·2 answers
  • What volume of silver metal will weigh exactly 2500g. The density of silver is 10,5 g/cubic centimeters.
    13·1 answer
  • Phagocytic cells perform their function by
    12·1 answer
  • URGENT HELP NEEDED! PLEASE ANSWER WITH EXPLANATION*
    13·1 answer
  • How many formulas units are in 3.11 mole of Ca(NO3)2 can you show your work by step by step correct answer
    15·2 answers
  • HEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEELLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP MEEEEEEEEEEEEEEEE
    14·2 answers
  • A hypothesis is tested by ___.
    9·1 answer
  • QUESTION 3
    14·1 answer
  • Hello people~
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!