1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
I am Lyosha [343]
4 years ago
7

Krypton-79 has a half-life of 35 hours. how many half-lives have passed after 105 hours?

Chemistry
1 answer:
Nookie1986 [14]4 years ago
6 0
The number of half -lives that has passed after 105  hours  for krypton-79 that has  half-life of 35 hours is calculated as below

if 1 half life = 35 hours

what about 105 hours = ? half-lives

= (1 half life  x105  hours) /35 hours = 3 half-lives  has passed after 105 hours
You might be interested in
3) Ha do vapor aod gases differ?
Neko [114]

Your question, I guess, How do vapour and gases differ...

Answer:

1.) Vapour is the changed state of any liquid either due to boiling or evaporation

2.) Vapour are more energetic as they have absorbed the latent heat of vaporization whereas Gases are low in energy because they are already in gaseous form at room temperature.

3.) Vapour have boiling points above room temperature while gases have their boiling point below room temperature.

6 0
3 years ago
Which of the following describes a situation where competition between producers exists
Oksanka [162]

Answer:

C. two or more producers are trying to sell the same good or service to the same consumers.

Explanation:

APEX

7 0
4 years ago
1.014)
Viefleur [7K]
The answer is B.Laws
7 0
3 years ago
Which statement best describes the formation of a solution?
aev [14]

Answer:

A small amount of solute dissolved in a larger amount of solvent.

Take this analogy to help you understand, if you were to put a teaspoon of sugar in a liter of water it would dissolve, but if you put a sack of sugar in it it would not dissolve! The solute is what is being dissolved and the solvent is what dissolves the solute, so that eliminates some of the options.

6 0
3 years ago
Calculate the number of joules of heat energy needed to increase the temperature of 25.0 g of metal from 21.0 ºC to 80.0 ºC. The
Harman [31]

Answer:

Q = 768.47 J

Explanation:

Given that,

Mass of the metal, m = 25 g

Initial temperature, T₁ = 21.0 ºC

Final temperature, T₂ = 80.0 ºC

The specific heat of the metal is 0.521 J/gºC.

We know that the heat released due to the change in temperature is given by :

Q=mc\Delta T\\\\=25\times 0.521\times (80-21)\\Q=768.47\ J

Hence, 768.47 J of heat energy will be needed.

7 0
3 years ago
Other questions:
  • A 6.0M solution HCl is diluted to 1.0M How many milliliters of the 6.0M solution would be used to prepare 100.o mL of the dilute
    5·2 answers
  • Molarity prctice c.10.c
    13·1 answer
  • Which is the best location for storing radioactive wastes?
    7·2 answers
  • Which type of energy transfer occurs when water is heated on a stove
    5·1 answer
  • It took 38.33 mL of 0.0944 M HCl to titrate (react completely with) the ammonia. What is the concentration of the original ammon
    14·1 answer
  • Convert 3.01€22 molecules of O²(a) mole of O²) ,volume at S.T.P,no of Oxygen atom. (d) mass​
    5·1 answer
  • What type of substance is reactant A?
    13·1 answer
  • A balloon has a volume of 105 Lif the temperature is 20 °C. If the temperature is -55°C,
    9·1 answer
  • When electricity passes through water (H20), the water breaks down to form
    13·2 answers
  • The molecular weight for the compound from the previous question is
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!