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Alex Ar [27]
3 years ago
7

What are five kinds of evidence you can use to determine if a chemical reaction has occurred?

Chemistry
1 answer:
telo118 [61]3 years ago
5 0
Change of odor, change of color, change of temperature, change of energy, or loss of heat
You might be interested in
What is an isotope? Give an example (use the full name! Simply listing the element is not a correct answer!)
Alina [70]

Answer:

Isotopes are variations of chemical elements that have the same number of protons but different number of neutrons.

Explanation:

3 0
3 years ago
Answer this ASAP please!! Question: How many magnesium atoms does magnesium oxide need? (Science) (ONLY ANSWER IF YOU KNOW WHAT
aliina [53]

Answer:

40.3 for the unit that represents the minimum amount of magnesium oxide I beilieve.

Explanation:

Magnesium atoms are heavier than oxygen atoms, so we expect more than 50% of magnesium in the weight composition. Taking just one atom of Mg and one atom of O you will get a mass of 16.0 + 24.3 = 40.3.

Hope this helps! Please tell me if you have any questions :))

7 0
3 years ago
a length of #8 copper wire (radius = 1.63 mm) has a mass of 24.0 Kg and a resistance of 2.061 Ohm per Km. What is the over all r
lubasha [3.4K]
V = m / ρ 
<span>V = (23,200/8.96) × 1000 </span>
<span>V = 2,589,285.71 mm³ </span>

<span>Now we have volume and given the radius we can solve for its length. </span>
<span>L = V/πr² </span>
<span>L = (2,589,285.71/(π×1.63²))/1×10^6 </span>
<span>L = 0.31 km </span>

<span>So </span>
<span>R = rL </span>
<span>R = 2.061(0.31) </span>
<span>R = .6389 Ω </span>

<span>End.</span>
6 0
3 years ago
Read 2 more answers
What volume of a 1.0 m HCL is required to completely neutralize 25.0 ml of a 1.0m KOH
yan [13]
To solve this equation you use the formula M_1V_1 = M_2V_2
M_1 = 1, V_1 = 25, M_2 = 1, V_2 = ?
Plug into the equation
1(25) = 1(V_2)
V_2 = 25 mL

7 0
4 years ago
What volume (in L) of a 6.84 M.
grandymaker [24]

Answer:

0.158L

Explanation:

From the question, we obtained the following information:

C1 = 6.84 M

V1 =?

C2 = 1.84 M

V2 = 588 mL = 588/1000 = 0.588L

Using the dilution formula C1V1 = C2V2. The original volume can calculated for as follows:

C1V1 = C2V2

6.84 x V1 = 1.84 x 0.588

Divide both side by 6.84

V1 =(1.84 x 0.588) / 6.84

V1 = 0.158L

4 0
3 years ago
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