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Alex Ar [27]
3 years ago
7

What are five kinds of evidence you can use to determine if a chemical reaction has occurred?

Chemistry
1 answer:
telo118 [61]3 years ago
5 0
Change of odor, change of color, change of temperature, change of energy, or loss of heat
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17)<br> How many grams are in 0.02 moles of beryllium iodide, Bel2?
Alinara [238K]

Answer:

beryllium iodide has a molar mass of 262.821 g mol−1 , which means that 1 mole of beryllium iodide has a mass of 262.821 g . To find the mass of 0.02 moles of beryllium iodide, simply multiply the number of moles by the molar mass in conversion factor form.

Explanation:

5 0
3 years ago
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When bridges are built, special joints must be used because the material of the bridge shrinks, and without these joints, the ma
marysya [2.9K]

Expansion

Explanation:

Expansion is the change is size of a body with increasing temperature and tension.

Bridges are built of iron. Iron thermally expands in the presence of increased temperature during the day. The length of the iron will increase by simple fractions. At night, when temperature drops, the bar returns back to its initial position.

  • The allowance for expansion of the metal is made in order to prevent tension within the structure.
  • Not doing this will cause the material to break since there is no free space for the bar to change shape.

Learn more:

Expansion in gases brainly.com/question/9979757

#learnwithBrainly

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3 years ago
What is the SI unit of mass?<br> Select one:<br> a.Ounce<br> b.Pound<br> c.Gram<br> d.Newton
Varvara68 [4.7K]

the SI unit of mass is kilogram

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3 years ago
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A mixture of methane and air is capable of being ignited only if the mole percent of methane is between 5% and 15%. A mixture co
DaniilM [7]

Answer:

Explanation:

The air 9% mole% methane have an average molecular weight of:

9%×16,04g/mol + 91%×29g/mol = 27,8g/mol

And a flow of 700000g/h÷27,8g/mol = 25180 mol/h

In the reactor where methane solution and air are mixed:

In = Out

Air balance:

91% air×25180 mol/h + 100% air×X = 95%air×(X+25180)

Where X is the flow rate of air in mol/h = <em>20144 mol air/h</em>

<em></em>

The air in the product gas is

95%×(20144 + 25180) mol/h = 43058 mol air× 21%O₂ = 9042 mol O₂ ×32g/mol = <em>289 kg O₂</em>

43058 mol air×29g/mol <em>1249 kg air</em>

Percent of oxygen is: \frac{289kg}{1249 kg} =<em>0,231 kg O₂/ kg air</em>

<em></em>

I hope it helps!

4 0
3 years ago
If you are studying cells and heredity bwhat classes are u in
ValentinkaMS [17]
Probably life science or biology.
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