Answer:
The sun.
Explanation:
It is closer to Earth, therefore bigger to us, and not just a small point of light.
Answer:
5. 56.5217
Explanation:
Calculate percent yield by (actual yield / theoretical yield) times 100
(13/23) x 100 = 56.52173913
A 2.200-g sample of quinone (C6H4O2) is burned in a bomb calorimeter whose total heat capacity is 7.854<span> kJ/°C. The temperature of the calorimeter increases from 23.44 to </span>30.57 °C<span>. </span>
Answer:
A. H₃O⁺ + CN⁻ → H₂O + HCN
B. OH⁻ + NH₄⁺ → NH₃ + H₂O
C. CN⁻ + NH₄⁺ → HCN + NH₃
D. HSO₄⁻ + CH₃COO⁻ → SO₄²⁻ + CH₃COOH
E. ClO⁻ + NH₃ → NO REACTION
Explanation:
Part A.
Sodium cyanide consist of Na⁺ and CN⁻ ions. CN⁻ is a conjugate base and accept H⁺ ion from nitric acid to form HCN (hydrogen cyanide).
Part B.
Ammonium chloride consist of NH₄⁺ and Cl⁻ ions. Sodium hydroxide is a strong base dissociate completely in solution convert into ammonium hydroxide and sodium chloride.
Part C.
Sodium cyanide consist of counter ion Na⁺ . CN⁻ combined with ammonium bromide to form ammonium cyanide and sodium bromide.
Part D.
Potassium hydrohen sulphate consist of potassium counter and hydrogen sulphate ion. Hydrogen sulphate combined with acetate ion to form acetic acid and sulphate ion.
Part E.
There have no reaction because hypochlorite and ammonia both are bases.
Answer:
a) Acidic buffer
b) No buffer
c) Acidic buffer
d) Basic buffer
e) Basic buffer
Explanation:
a) 75.0 mL of 0.10 M HF ; 55.0 mL of 0.15 M NaF
-Acidic buffer
Mixing of 75.0 mL of 0.10 HF and 55.0 mL of 0.15 mL NaF results in acidic buffer. HF/NaF is a buffer of weak acid and its conjugate base. F- is the conjugate base of acid,HF.
b.) 150.0 mL of 0.10 M HF ; 135.0 mL of 0.175 M HCl-No buffer
Mixing HF and HCl will not results in a buffer. Both are acids, and no conjugate base is present.
c.) 165.0 mL of 0.10 M HF ; 135.0 mL of 0.050 M KOH-Acidic buffer
HF reacts with KOH to form KF. F- is a conjujate base of HF. As volume and concentration of HF is more than KOH, therefore, HF will remain after reaction with KOH. HF/KF will be a buffer of weak acid and its conjugate base.
d.) 125.0 mL of 0.15 M CH3NH2 ; 120.0 mL of 0.25 M CH3NH3Cl -Basic buffer
CH3NH2/CH3NH3+ is a buffer of weak base and its conjugate acid.
e.) 105.0 mL of 0.15 M CH3NH2 ; 95.0 mL of 0.10 M HCl-Basic buffer
CH3NH2 is a weak base and HCl is a strong acid. CH3NH2 reacts with HCl to form its conjugate acid CH3NH3+. Volume and concentration of CH3NH2 is more as compared to HCl and hence, will remain in the soution after reactionf with HCl.
CH3NH3+/CH3NH2 is a buffer of weak base and its conjugate acid.
