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masha68 [24]
3 years ago
7

When planning an experiment, a scientist must first choose a question to investigate. In an experiment, Renata changes the relea

se height of the steel ball and measures the distance the ball travels from the ramp before falling to the ground. Based on this procedure, which question is Renata investigating?A) How is the ball's speed affected by the release height from a ramp?B) How does the release height of a ball on ramp affect the amount of time that passes before the ball hits the floor?C) How much force does the ball exert when it strikes the floor?D) How does the release high of a ball on a ramp effect the distance it travels from the ramp before falling to the floor?
Physics
1 answer:
dangina [55]3 years ago
6 0

Answer:

The correct option is D

Explanation:

In the course of the experiment, two key phrases/variables defined the experiment done,

i) the release height of the steel ball (independent variable)

ii) the distance the ball travels from the ramp before falling to the ground (dependent variable)

The only option that contains and relates this two variables as carried out during the course of the experiment is option D.

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almond37 [142]

Answer:

2s worth of falling up

Explanation:

7 0
3 years ago
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Under what circumstances will the distance traveled by an object be the same as the magnitude of the displacement of an object?​
KiRa [710]
Hi Randa, want me to help you with physics? The answer is when the object moves in a straight line.
5 0
2 years ago
Use the work-energy theorem to determine the force required to stop a 1000 kg car moving at a speed of 20.0 m/s if there is a di
Vlad1618 [11]

Answer:

4.44 kN in the opposite direction of acceleration.

Explanation:

Given that, the initial speed of the car is, u=20m/s

And the mass of the car is, m=1000 kg

The total distance covered by the car before stop, s=45m

And the final speed of the car is, u=0m/s

Now initial kinetic energy is,

KE_{i}=\frac{1}{2}mu^{2}

Substitute the value of u and m in the above equation, we get

KE_{i}=\frac{1}{2}(1000kg)\times (20)^{2}\\KE_{i}=20000J

Now final kinetic energy is,

KE_{f}=\frac{1}{2}mv^{2}

Substitute the value of v and m in the above equation, we get

KE_{f}=\frac{1}{2}(1000kg)\times (0)^{2}\\KE_{i}=0J

Now applying work energy theorem.

Work done= change in kinetic energy

Therefore,

F.S=KE_{f}-KE_{i}\\F\times 45=(0-200000)J\\F=\frac{-200000J}{45}\\ F=-4444.44N\\F=-4.44kN

Here, the force is negative because the force and acceleration in the opposite direction.

6 0
2 years ago
A person hums into the top of a well (tube open at only one end) and finds that standing waves are established at frequencies of
S_A_V [24]

Answer:

Explanation:

The resonance in a tube that is open at one end and closed at the other, we can find it because in the closed part you have a node and in the open part you have a belly, so for the fundamental frequency you have ¼ Lam, the different resonances are:

Fundamental              λ = 4L

3 harmonica               λ  = 4L / 3

5 Harmonica               λ = 4L / 5

General harmonica     λ = 4L / (2n-1)                n = 1, 2, 3

Let's apply this equation to our case

The speed of sound is given by

          v =  λ  f

          λ = v / f

Let's look for wavelengths

         λ₁ = 40.6 / 343 = 0.1184 m

         λ₂ = 67.7 / 343 = 0.1974 m

         λ₃ = 94.7 / 343 = 0.2761 m

Since the wavelengths are close we can assume that it corresponds to consecutive integers, where for the first one it corresponds to the integer n

          λ ₁ = 4L / (2n-1)

          λ₂ = 4L / (2 (n + 1) -1) = 4L / (2n +1)

          λ₃ = 4L / (2 (n + 2) -1) = 4L / (2n + 3)

Let's clear in the first and second equations

          2n-1 = 4L / λ₁

          2n +1 = 4L / λ₂

Let's solve the system of equations

         4L / λ₁ + 1 = 4L / λ₂ -1

         4L / λ₂ – 4L / λ₁ = 2

         2L (1 / λ₂ - 1 / λ₁) = 1

         1 / L = 2 (1 / λ₂ -1 / λ₁)

         1 / L = 2 (1 / 0.1974 - 1 / 0.1184)

         1 / L = 2 (5,066 - 8,446) = -6.76

         L = 0.1479 m

3 0
3 years ago
A puppy is running with a speed of 11.2 m/s towards it owner when it
Levart [38]

Answer:

-5.6m/s²

Explanation:

Given parameters:

Initial speed  = 11.2m/s

Time of running  = 2s

Unknown:

Acceleration of the puppy  = ?

Solution:

Acceleration is the rate of change of velocity with time.

So;

   Acceleration  = \frac{Final speed  - initial speed }{time}  

final speed  = 0m/s

 Acceleration  = \frac{0 - 11.2}{2}    = -5.6m/s²

8 0
2 years ago
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