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masha68 [24]
3 years ago
7

When planning an experiment, a scientist must first choose a question to investigate. In an experiment, Renata changes the relea

se height of the steel ball and measures the distance the ball travels from the ramp before falling to the ground. Based on this procedure, which question is Renata investigating?A) How is the ball's speed affected by the release height from a ramp?B) How does the release height of a ball on ramp affect the amount of time that passes before the ball hits the floor?C) How much force does the ball exert when it strikes the floor?D) How does the release high of a ball on a ramp effect the distance it travels from the ramp before falling to the floor?
Physics
1 answer:
dangina [55]3 years ago
6 0

Answer:

The correct option is D

Explanation:

In the course of the experiment, two key phrases/variables defined the experiment done,

i) the release height of the steel ball (independent variable)

ii) the distance the ball travels from the ramp before falling to the ground (dependent variable)

The only option that contains and relates this two variables as carried out during the course of the experiment is option D.

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Answer:

x = 27.3 m

Explanation:

This is a projectile launching exercise, let's start by looking for the time it takes for the rock to reach the height of the window.

Let's use trigonometry to find the velocities of the rock

           sin 40 = v_{oy} / v

           cos 40 = v₀ₓ / v

           v_{oy}= v sin 40

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we look for the time

        v_{y}^2 = v_{oy}^2 - 2 g y

         v_{y}^2 = 19.28 2 - 2 9.8 16 = 371.71 - 313.6 = 58.118

        v_{y} = 7.623 m / s

we calculate the time

          v_{y} = v_{oy} - gt

          t = (v_{oy} - v_{y}) / g

          t = (19.28 -7.623) / 9.8

          t = 1,189 s

           

since the time is the same for both movements let's use this time to find the horizontal distance

           x = v₀ₓ t

           x = 22.98 1,189

           x = 27.3 m

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