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True [87]
3 years ago
7

Fossils of a species of beaver are found in layer 6. which layer is most likely to have organisms that have lived at the same ti

me as the beavers species?

Chemistry
2 answers:
saul85 [17]3 years ago
6 0

Answer: Layer 5

Explanation:

The beavers are the species that lived at the time that when they formed fossil they attained the layer number 6.

The other animals or plant species that lived at that time will be found close to the layer number 6.

The layer close to layer 6 is number 5, so the species that lived at the same time as the beavers species will be here only.

Hence, the correct answer is option C

Dovator [93]3 years ago
3 0

Layer 5 would be the most likely. The shift up into layer 6 would both mix the already found fossils and its own. Plus, the layers are close as it is

I hope this helps!

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5. 1.00 mol HNO3 is treated with 4.47 g of magnesium. Calculate the number of moles of
ruslelena [56]

Answer:

The balanced equation is:

2 HNO3 + Mg ---> Mg(NO3)2 + H2

From the equation, we can see that we need twice the moles of HNO3 than the moles of Mg

Moles of Mg:

Molar mass of Mg = 24 g/mol

Moles = Given mass / Molar Mass

Moles of Mg = 4.47 / 24 = 0.18 moles (approx)

Hence, 2(moles of Mg) = 0.36 moles of HNO3 will be consumed

Number of moles of HNO3 after the reaction is finished is the number of unreacted moles of HNO3

Unreacted moles of HNO3 = Total Moles - Moles consumed

Unreacted moles of HNO3 = 0.64 moles (approx)

Since we approximated the value of moles of Mg, the value of remaining moles of HNO3 will also be approximate

From the given options, we can see that 0.632 moles is the closest value to our answer

Therefore, 0.632 moles will remain after the reaction

3 0
4 years ago
Why can liquids change shape but solids cannot
Cerrena [4.2K]

Answer:

Explanation:

the forces between the molecules are stronger in solid than in liquids

5 0
3 years ago
Think of an everyday situation in which two objects interact and exert a force on each other. Explain how the interaction can ca
blondinia [14]

Answer:

It's explained below.

Explanation:

An everyday situation is when we raise an object.

Now, when we raise an object, energy is transferred to the Earth object system and thus the gravitational field energy of the system will increase.

Now, this energy is usually released when the object falls. The mechanism of this release is known as gravitational force.

In the same manner, two magnetic and electrically charged objects that are interacting at a distance will exert forces on each other and this can lead to transfer of energy between the interacting objects.

6 0
3 years ago
If the detector is capturing 3.3×108 photons per second at this wavelength, what is the total energy of the photons detected in
Reil [10]

Answer:

The total energy of the photons detected in one hour is 7.04*10⁻¹¹ J

Explanation:

The energy carried by electromagnetic radiation is displaced by waves. This energy is not continuous, but is transmitted grouped into small "quanta" of energy called photons. The energy (E) carried by electromagnetic radiation can be measured in Joules (J). Frequency (ν or f) is the number of times a wave oscillates in one second and is measured in cycles / second or hertz (Hz). The frequency is directly proportional to the energy carried by a radiation, according to the equation: E = h.f, (where h is the Planck constant = 6.63 · 10⁻³⁴ J / s).

Wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. it is expressed in units of length (m). In light and other electromagnetic waves that propagate at the speed of light (c), the frequency would be equal to the speed of light (≈ 3 × 10⁸ m / s) between the wavelength :

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E=\frac{h*speed of light}{wavelength}

In this case, the wavelength is 3.35mm=3.35*10⁻³m and the energy per photon is:

E=\frac{6.63*10^{-34}*3*10^{8}}{3.35*10^{-3} }

E=5.93*10⁻²³ \frac{J}{proton}

The detector is capturing  3.3*10⁸ photons per second. So, in 1 hour:

E=5.93*10^{-23} \frac{J}{proton} *3.3*10^{8} \frac{proton}{s} *\frac{60}{1} \frac{s}{minute} *\frac{60}{1} \frac{minute}{hr}

E=7.04*10⁻¹¹ \frac{J}{hr}

The total energy of the photons detected in one hour is 7.04*10⁻¹¹ J

3 0
3 years ago
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