Answer:
For 1 hour 75w light bulb requires 270 kj for burning
for 3 hours 75 w light bulb requires 270*3 = 810kj for burning
Explanation:
No two electrons in an atom<span> can have exactly the same </span>quantum<span> numbers. Orbital </span>quantum<span> numbers tell you what energy level the electron is in. In the Bohr</span>model<span>, this represents how high the orbit is above the nucleus; higher orbits have more energy</span>
<span>First divide the ionization energy by Avogadro's number to get the energy per atom of potassium;
</span>419 kj/mol / 6.023 x 10²³
= 4.19 x 10⁵ / 6.023 x 10²³ = 6.96 x 10⁻¹⁹
E = hc/λ
where lambda (λ<span>) is the wavelength, h is Planck's constant, c is the speed of light
</span>E = 6.96 x 10⁻¹⁹ j/atom<span>
h =</span>6.63x10⁻³⁴<span> Js
c = 3 x 10</span>⁸ m/s
λ = ?
λ = hc/E = (6.63x10⁻³⁴ x 3 x 10⁸ ) / 6.96 x 10⁻¹⁹ = 285.8nm = 286nm
<span>The longest wavelength of light capable of this ionization is 286nm.</span>
Hello,
I think the answer is B) It is second longest river in south america
Hope this helps!!
~Girlygir101~
