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3 years ago

Resolve the following two forces into horizontal and vertical components.

Physics

1 answer:

WITCHER [35]3 years ago

6 0

All components of both forces have zero magnitudes.

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g A box having mass 0,5kg is placed in front of a 20 cm compressed spring. When the spring released, box having mass m1, collide

vagabundo [1.1K]

Answer:Expression given below

Explanation:

Given mass of spring $\left ( m_1\right )=0.5 kg$

Compression in the spring $\left ( x\right )=20 cm$

Let the spring constant be K

Using Energy conservation

potential energy stored in spring =Kinetic energy of Block $\left ( m_1\right )$

$\frac{1}{2}Kx^2=\frac{1}{2}m_1v^2$

$v=x\sqrt{\frac{k}{m_1}}$

now conserving momentum

$m_1v=\left ( m_1+m_2\right )v_0$

$v_0=\frac{m_1}{m_1+m_2}v$

where $v_0$ is the final velocity

3 0

4 years ago

Under water, Zachary can hear waves that travel with frequencies up to 15,000 Hz. What is the velocity of sound in water if a wa

harina [27]

Answer:

18 000 m/ s

Explanation:

speed = wavelength * frequency

speed = 1.2 * 15 000 = 18 000 m/s

4 0

2 years ago

Nitrogen gas (N2) and hydrogen gas (H2) combine to form ammonia (NH3). Which equation correctly represents this reaction?

sweet [91]

Answer:

The correctly equation is D) N2+ 3H2 → 2NH3

Explanation:

Both nitrogen and hydrogen are presented in bimolecular form (N2 and H2), on one side and on the other side of the equation we have 2 Nitrogens and 6 Hydrogens (it is balanced)

5 0

4 years ago

An object-spring system undergoes simple harmonic motion with an amplitude A. Does the total energy change if the mass is double

son4ous [18]

Answer: No, The energy will remain the same

Explanation: Doubling the mass and leaving the amplitude unchanged won't have any effect on the total energy of the system.

At maximum displacement, E=0.5kA^2

Where E = total energy

K = spring constant

A = Amplitude

From the formula above : Total Energy is independent of mass,. Therefore, total energy won't be affected by Doubling the mass value of the object.

Also when the object is at a displacement 'x' from its equilibrium position.

E = Potential Energy(P.E) + Kinetic Energy(K.E)

P.E = 0.5kx^2

Where x = displacement from equilibrium position

E = Total Energy

K. E= E-0.5kx^2

From the relation above, total energy is independent of its mass and therefore has no effect on the total energy.

6 0

4 years ago

Two small insulating spheres with radius 3.50×10−2 m are separated by a large center-to-center distance of 0.555 m. One sphere i

xz_007 [3.2K]

Answer:

$E = 7.83 \times 10^5 N/C$

Explanation:

Since we know that two sphere is oppositely charged so net electric field at the mid point of two balls will be sum of the electric field due to each ball at the mid point

So we know that

$E = \frac{kq_1}{r^2} + \frac{kq_2}{r^2}$