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Iteru [2.4K]
3 years ago
5

Apply a force of 50 N right to the box. Describe the motion of the box using physics terms (i.E. Velocity, acceleration, displac

ement). Refer to the speedometer in your answer.
Physics
1 answer:
Nikitich [7]3 years ago
4 0

When unbalanced force is acting on the system of mass then as per Newton's II law we can say

F_{net} = ma

here we have

a = \frac{F}{m}

now since the force and mass both given to us so we can find acceleration of object from this

now when 50 N force is applied on a box then this 50 N force is unbalanced force on it and it will produce acceleration to the box

So here we can say that box will accelerate with constant acceleration and hence its velocity will linearly increase with time.

Now the displacement of the object will be given as

d = v_i * t + \frac{1}{2} at^2

so here the displacement will be a quadratic function of time and increases with time as well

so here overall the motion will be of constant acceleration, uniformly  increasing velocity and displacement will be a quadratic function of time

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At t = 0, a car registers at 30 miles/hr. Forty seconds later, the car’s velocity is now at 50 miles/hr. Assuming constant accel
ratelena [41]
D.

50 mph - 30 mph= 20 mph net velocity
change.
20mph/3600 seconds/hour= .00555 MPS
.0055 miles per second


40 seconds to complete the change
.0055/40= .000138

7 0
3 years ago
PLS HELP FIND THE AVREGE KENETIC ENERGY!!
ANEK [815]

Answer: if you gogle it it will tell you the awenser

lanation:

4 0
3 years ago
Calculate the average times it took the car to travel 0. 25 and 0. 50 meters. Record the averages, to two decimal places, in Tab
Illusion [34]

The average speed of the given car is 2.22 s and 3.13 s for 0.25 m and 0.50 m distance respectively.

<h3>How to calculate the Average speed?</h3>

The average speed can be calculated by adding the speed of each trial divided by the number of trials,

For 0.25 m the average speed will be:

S_{avg} = \dfrac{2.24 + 2.21 + 2.23}{ 3}\\\\S_{avg} = 2.22

For the 0.50 m, the average speed will:

S_{avg} = \dfrac {3.16 + 3.08 + 3.15} {3 }\\\\S_{avg}  = 3.13\rm \  s

Therefore, the average speed of the given car is 2.22 s and 3.13 s for 0.25 m and 0.50 m distance respectively.

Learn more about Average speed:

brainly.com/question/26386984

6 0
2 years ago
A stuntman with a mass of 80.5 kg swings across a moat from a rope that is 11.5 m. At the bottom of the swing the stuntman's spe
goldenfox [79]

Answer:

  • No
  • 5.49 m/s

Explanation:

The net force required to accelerate the stuntman in a circular arc of radius 11.5 m will be ...

  F = mv²/r . . . . where this m is the mass being accelerated, v is the tangential velocity, and r is the radius.

Here, the net force needs to be ...

  F = (80.5 kg)(8.45 m/s)²/(11.5 m) . . . . . where this m is meters

  ≈ 499.8175 kg·m/s² = 499.8 N

Gravity exerts a force on the stuntman of ...

  F = mg = (80.5 kg)(9.8 m/s²) = 788.9 kg·m/s² = 788.9 N

Then the tension required in the rope/vine is ...

  499.8 N+788.9 N= 1288.7 N

This is more than the capacity of the rope, so we do not expect the stuntman to make it across the moat.

_____

The allowed net force for centripetal acceleration is ...

  1000 N -788.9 N = 211.1 N

Then the allowed velocity is ...

  211.1 = 80.5v²/11.5

  30.16 = v² . . . .  multiply by 11.5/80.5

  5.49 = v . . . . . . take the square root

The maximum speed the stuntman can have is 5.49 m/s.

_____

<em>Comment on crossing the moat</em>

The kinetic energy at the bottom of the swing translates to potential energy at the end of the swing. At the lower speed, the stuntman cannot rise as high, so will traverse a shorter arc. At 8.45 m/s, the moat could be about 16.8 m wide; at 5.49 m/s, it can only be about 11.5 m wide.

5 0
3 years ago
Vivian went on a bicycle trip through Germany with her family. One afternoon, she rode her bicycle along a long flat road at a c
natima [27]

d = distance traveled by her on her bicycle on a long flat road = 24 kilometer

t = time taken by her to travel distance "d" on her bicycle on a long flat road = 1.2 hours

v = average speed of vivian = ?

we know that average speed is given as

v = d/t

inserting the values in the above formula

v = 24 kilometer / 1.2 hour

v = 20 kilometer/hour


hence the correct choice is

C) 20 km/h



8 0
3 years ago
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