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Iteru [2.4K]
3 years ago
5

Apply a force of 50 N right to the box. Describe the motion of the box using physics terms (i.E. Velocity, acceleration, displac

ement). Refer to the speedometer in your answer.
Physics
1 answer:
Nikitich [7]3 years ago
4 0

When unbalanced force is acting on the system of mass then as per Newton's II law we can say

F_{net} = ma

here we have

a = \frac{F}{m}

now since the force and mass both given to us so we can find acceleration of object from this

now when 50 N force is applied on a box then this 50 N force is unbalanced force on it and it will produce acceleration to the box

So here we can say that box will accelerate with constant acceleration and hence its velocity will linearly increase with time.

Now the displacement of the object will be given as

d = v_i * t + \frac{1}{2} at^2

so here the displacement will be a quadratic function of time and increases with time as well

so here overall the motion will be of constant acceleration, uniformly  increasing velocity and displacement will be a quadratic function of time

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If a compound has a very low melting and boiling point, it is likely that the compound possesses mainly which type of intermolec
sergejj [24]
For the given question above, I think there is an associated choice of answer for it. However, the answer for this is London Dispersion Forces. <span>Dipole-dipole forces and hydrogen bonding are much stronger, leading to higher melting and boiling points.</span>
6 0
3 years ago
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Arturiano [62]
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4 0
2 years ago
When you jump from an elevated position you usually bend your knees upon reaching the ground. By doing this, you make the time o
dsp73

Answer:

c. about 1/10 as great.

Explanation:

While jumping form a certain height when we bend our knees upon reaching  the ground such that the time taken to come to complete rest is increased by 10 times then the impact force gets reduced to one-tenth of the initial value when we would not do so.

This is in accordance with the Newton's second law of motion which states that the rate of change in velocity is directly proportional to the force applied on the body.

Mathematically:

F\propto\frac{d}{dt} (p)

\Rightarrow F=\frac{d}{dt} (m.v)

since mass is constant

F=m\frac{d}{dt}v

when dt=10t

then,

F'=m.\frac{v}{10\times t}

F'=\frac{1}{10} \times \frac{m.v}{t}

F'=\frac{F}{10} the body will experience the tenth part of the maximum force.

where:

\frac{d}{dt} = represents the rate of change in dependent quantity with respect to time

p= momentum

m= mass of the person jumping

v= velocity of the body while hitting the ground.

7 0
3 years ago
A line from the Brackett series of hydrogen has a wavelength of 1945nm (or 1.0979x10^7m). From which state did the electron orig
Zarrin [17]
We use the Rydberg Equation for this which is expressed as:

<span>1/ lambda = R [ 1/(n2)^2 - 1/(n1)^2]
</span>
where lambda is the wavelength, where n represents the final and initial states. Brackett series means that the initial orbit that electron was there is 4 and R is equal to 1.0979x10^7m<span>. Thus,
</span>
1/ lambda = R [ 1/(n2)^2 - 1/(n1)^2]
1/1.0979x10^7m = 1.0979x10^7m [ 1/(n2)^2 - 1/(4)^2]

Solving for n2, we obtain n=1.
5 0
3 years ago
Suppose a wheel with a tire mounted on it is rotating at the constant rate of 2.23 2.23 times a second. A tack is stuck in the t
elena-14-01-66 [18.8K]

Explanation:

The given data is as follows.

       Angular velocity (\omega) = 2.23 rps

     Distance from the center (R) = 0.379 m

First, we will convert revolutions per second into radian per second as follows.

             = 2.23 revolutions per second

             = 2.23 \times 2 \times 3.14 rad/s

             = 14.01 rad/s

Now, tangential speed will be calculated as follows.

  Tangential speed, v = R \times \omega

                               = 0.379 x 14.01

                               = 5.31 m/s

Thus, we can conclude that the tack's tangential speed is 5.31 m/s.

8 0
3 years ago
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