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Iteru [2.4K]
3 years ago
5

Apply a force of 50 N right to the box. Describe the motion of the box using physics terms (i.E. Velocity, acceleration, displac

ement). Refer to the speedometer in your answer.
Physics
1 answer:
Nikitich [7]3 years ago
4 0

When unbalanced force is acting on the system of mass then as per Newton's II law we can say

F_{net} = ma

here we have

a = \frac{F}{m}

now since the force and mass both given to us so we can find acceleration of object from this

now when 50 N force is applied on a box then this 50 N force is unbalanced force on it and it will produce acceleration to the box

So here we can say that box will accelerate with constant acceleration and hence its velocity will linearly increase with time.

Now the displacement of the object will be given as

d = v_i * t + \frac{1}{2} at^2

so here the displacement will be a quadratic function of time and increases with time as well

so here overall the motion will be of constant acceleration, uniformly  increasing velocity and displacement will be a quadratic function of time

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a body of mass 0.2kg is whirled round a horizontal circle by a string inclined at 30 degrees to the vertical calculate <br /&
Katen [24]

Answer:

a)  T = 2.26 N, b) v = 1.68 m / s

Explanation:

We use Newton's second law

Let's set a reference system where the x-axis is radial and the y-axis is vertical, let's decompose the tension of the string

        sin 30 = \frac{T_x}{T}

        cos 30 = \frac{T_y}{T}

        Tₓ = T sin 30

        T_y = T cos 30

Y axis  

       T_y -W = 0

       T cos 30 = mg                     (1)

X axis

        Tₓ = m a

they relate it is centripetal

        a = v² / r

we substitute

         T sin 30 = m\frac{v^2}{r}            (2)

a) we substitute in 1

         T = \frac{mg }{cos 30}

         T = \frac{ 0.2 \ 9.8}{cos  \ 30}

         T = 2.26 N

b) from equation 2

           v² = \frac{T \ sin 30 \ r}{m}

If we know the length of the string

          sin 30 = r / L

          r = L sin 30

we substitute

          v² = \frac{ T \ sin 30 \ L \ sin 30}{m}

          v² = \frac{TL \ sin^2  30}{m}

For the problem let us take L = 1 m

let's calculate

          v = \sqrt{ \frac{2.26 \ 1 \ sin^230}{0.2} }

          v = 1.68 m / s

8 0
2 years ago
A 30° incline permanently sits on a 1.1 meter high table. Starting from rest a ball rolls off the incline with a velocity of 2m/
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2 years ago
what does the density of an object tell you about the molecular arrangement of the atoms in an object
Andrews [41]

Answer:

If the density of the object is high its molecular arrangement is compact while if the density is lows its molecular arrangement isnt that compact

4 0
2 years ago
Help with #3 please
Marizza181 [45]

Answer:

The answer to your question is va = 8 cm/s, vb = 12.5 cm/s, a = 9 cm/s²

Explanation:

Data

Ta = 0.125 s

Tb = 0.08 s

Δtab = 0.5 s

distance = 1 cm

Process

1.- Calculate va

va = 1/0.125 = 8 cm/s

vb = 1/0.08 = 12.5 cm/s

2.- Calculate Δv

Δv = 12.5 - 8

Δv = 4.5 cm/s

3.- Calculate acceleration

a = Δv / Δt

a = 4.5/0.5

a = 9 cm/s²

4 0
2 years ago
Indicate on the chart whether you would classify each model as representing an element, compound, or mixture.
Ne4ueva [31]

Answer:

1 compound

2 mixture

3 elements

4 0
3 years ago
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