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Iteru [2.4K]
3 years ago
5

Apply a force of 50 N right to the box. Describe the motion of the box using physics terms (i.E. Velocity, acceleration, displac

ement). Refer to the speedometer in your answer.
Physics
1 answer:
Nikitich [7]3 years ago
4 0

When unbalanced force is acting on the system of mass then as per Newton's II law we can say

F_{net} = ma

here we have

a = \frac{F}{m}

now since the force and mass both given to us so we can find acceleration of object from this

now when 50 N force is applied on a box then this 50 N force is unbalanced force on it and it will produce acceleration to the box

So here we can say that box will accelerate with constant acceleration and hence its velocity will linearly increase with time.

Now the displacement of the object will be given as

d = v_i * t + \frac{1}{2} at^2

so here the displacement will be a quadratic function of time and increases with time as well

so here overall the motion will be of constant acceleration, uniformly  increasing velocity and displacement will be a quadratic function of time

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Consider the following three statements: For any electromagnetic radiation, the product of the wavelength and the frequency is a
boyakko [2]

Answer:

The correct answer is B. Statements (i) and (ii) are true.

Explanation:

<u>Fisrt statement:</u>

Electromagnetic radiation such as wave, wavelength λ and oscillation frequency ν are related by a constant, the speed of light. The equation is given by:

c= \lambda \nu

So the first statement is true.

<u>Second statement:</u>

c=\lambda \nu\\c= 3.0 A \times 1.0\times 10^{18} Hz\\c= 3.0\times 10^{-10} m  \times 1.0\times 10^{18} s^{-1}\\c=3\times 10^8 \frac{m}{s}

The value of c in the vacuum is 3×10⁸ m/s. Hence, the second statement is true.

<u>Third statement:</u>

The speed of any electromagnetic radiation is constant regardless the type of radiation.

Hence, the third statement is false.

8 0
3 years ago
A 0.10 kg baseball travelling at 40 m s−1 hits straight back to the pitcher at 55 m s−1. The contact time is 0.01 seconds. What
Ilia_Sergeevich [38]

Answer:

1.5 kgms⁻¹

Explanation:

Momentum can be defined as "<em>mass in motion</em>."  

The amount of momentum that an object has is dependent upon two factors

  • mass of the moving object  
  • speed of motiom 

when there is a change in the velocity , it creates a change in momentum also

when we consider that we can mathematically show this,In terms of an equation,

Change in momentum    (ΔΡ) = m(Δv)

where (Δv) - change in velocity

<em>(Δv) = final velocity - initial velocity</em>

Change in momentum (ΔΡ) = m(Δv)

                                             = 0.1×([55-40])

                                             = 1.5 kgms⁻¹

     

7 0
3 years ago
A tennis ball is hit at an angle of 20° to the horizontal with the velocity of 20 m/s. What is its velocity in the Y direction?
Alona [7]
B Hopefully I Helped... Good Luck
3 0
3 years ago
Compare and contrast the general characteristics of a gas giant planet and one of the inner planets (such as Mercury, Earth, Ven
yKpoI14uk [10]
The gas planets usually have extremely high gravitational pulls, the surface isn't solid (since its a gas planet), and gas planets are larger than the inner planets. 
<span>Similarities- These planets all have moons and they both revolve around the sun (obviously).


Hope this helps.</span>
6 0
3 years ago
A 2.74 g coin, which has zero potential energy at the surface, is dropped into a 12.2 m well. After the coin comes to a stop in
VikaD [51]

Answer:

B. - 0.328

Explanation

Potential Energy:<em> This is the energy of a body due to position.</em>

<em>The S.I unit of potential energy is Joules (J).</em>

<em>It can be expressed mathematically as</em>

<em>Ep = mgh........................... Equation 1</em>

<em>Where Ep = potential energy, m = mass of the coin, h = height, g = acceleration due to gravity,</em>

<em>Given: m = 2.74 g = 0.00274 kg, h = 12.2 m, g = 9.8 m/s²</em>

Substituting these values into equation 1

Ep = 0.00274×12.2×9.8

Ep = 0.328 J.

Note: Since the potential energy at the surface is zero, the potential Energy with respect to the surface = -0.328 J

The right option is B. - 0.328

<em />

7 0
3 years ago
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