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DanielleElmas [232]
2 years ago
15

A 10248 kg car is pulled by a low tow truck that has an acceleration of 2.0m/s what is the net force on the car

Physics
1 answer:
Ksenya-84 [330]2 years ago
8 0

Answer: 20496N

Explanation:

The formula to calculate the net force will be given as:

Net force = Acceleration × Mass

Since 10248 kg car is pulled by a low tow truck that has an acceleration of 2.0m/s, the net force would be:

= 10248 × 2

= 20496N

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El. A horizontally directed force of 40 N is used to pull a box a distance of 2.5 m across a tabletop. How much work is done by
PIT_PIT [208]

The same formula of work can be applied to all the questions. The answers are:

E1. 100J

E2. 40N

E3. 5m

E4. a.) 360 J           b.) 240 J               c.) 120 J

El. If a horizontally directed force of 40 N is used to pull a box a distance of 2.5 m across a tabletop. The formula to get the much work that will be done by the 40 - N force will be

Work done = force x distance

Work done = 40 x 2.5

Work done = 100 J

E2. If a woman does 160 J of work to move a table 4 m across the floor. We will use the same formula to calculate the magnitude of the force that the woman applied to the table assuming the force is applied in the horizontal direction.

Work done = force x distance

160 = 4F

F = 160/4

Force F = 40 N

E3. Given that a force of 60 N used to push a chair across a room does 300 J of work. Same formula to get how far the chair move in this process.

Work done = force x distance

300 = 60 x distance

distance = 300/60

Distance = 5 m

Therefore, the chair moved 5m away.

E4. Given that a rope applies a horizontal force of 180 N to pull a crate a distance of 2 m across the floor. And a frictional force of 120 N opposes this motion.

a. The work done by the force applied by the rope can  be found by

W = F x S

W = 180 x 2

W = 360 J

b. What is the work done by the frictional force?

W = F_{r} x s

W = 120 x 2

W = 240 J

c. What is the total work done on the crate?

W = (F - F_{r}) x distance

Where  F_{r}  = frictional force

Substitute all the parameters

W = (180 - 120) x 2

W = 60 x 2

W = 120 J

Learn more about work here: brainly.com/question/8119756

4 0
2 years ago
A rectangular block floats in pure water with 0.400 in. above the surface and 1.60 in. below the surface. When placed in an aque
labwork [276]

Answer:

specific gravity = 0.8

specific gravity of  solution  = 2

Explanation:

given data

rectangular block above water  = 0.400 in

rectangular block below water = 1.60 in

material floats below water = 0.800 in

solution

first we get here specific gravity of block  that is

specific gravity = block vol below ÷ total block vol × specific gravity  water   ..............1

put here value we get

specific gravity =  \frac{1.60}{1.60+0.400}  × 1

specific gravity = 0.8

and now we get here specific gravity of  solution  that is express as

specific gravity of  solution  = total block vol ÷ block vol below × specific gravity  block   ........................2

put here value we get

specific gravity of  solution  = \frac{1.60+0.400}{0.800} × 0.8

specific gravity of  solution  = 2

6 0
3 years ago
What is the mass of an 291pound persond
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Well, it also depends on the height... but say if they were 5'3" and 291 pounds...
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51.55
4 0
3 years ago
In order to protect underground pipelines and storage tanks made of iron, the iron is made the cathode of a voltaic cell through
emmasim [6.3K]

The answer would be that the process to protect the underground pipelines and storage tanks is cathodic protection.

3 0
3 years ago
A bicyclist notes that the pedal sprocket has a radius of rp = 9.5 cm while the wheel sprocket has a radius of rw = 4.5 cm. The
ANTONII [103]

Answer:

Explanation:

a) ωp = 2π radians / 1.7 s = <u>3.7 rad/s</u>

b) ωs = 3.7 rad/s(9.5 cm / 4.5 cm) = 7.8 rad/s

  v = (ωs)R = 7.8(65) = 507 cm/s or <u>5.1 m/s</u>

c) ωs = 3.5 m/s / 0.65 m = 5.38 rad/s

ωp = 5.38(4.5 cm / 9.5 cm) = 2.55 rad/s

t = θ/ω = 2π / 2.55 = 2.463... <u>2.5 s</u>

4 0
3 years ago
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