Answer:
Energy needed = 54.02 J
Explanation:
the Energy in an elastic spring from hookes law is given as
F= ke , therefore the energy (E) is
E =
K = 19.5 N/cm
e = 1.39cm
E = x 19.5 x 1.39
E = 13.55 J
The energy to stretch the spring for 6.93cm is
E = x 19.5 x 6.93
E = 67.57 J
The more energy needed for the further stretch is
67.57 - 13.55
Energy needed = 54.02 J
The average velocity of the fly between 0 and 15 seconds will be 10 m/sec.Velocity is the time-based component.
<h3>What is average velocity?</h3>
The average velocity is the ratio of the total distance traveled to the total time taken by the body. Its unit is m/sec.
From the given graph it is obsderved that the displacement from 0 to 15 seconds will be 150 m.
Hence the average velocity of the fly between 0 and 15 seconds will be 10 m/sec.
To learn more about the average velocity refer to the link;
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