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2 years ago

What's the average speed of an object moving 3790 meters in 249 s.

Physics

1 answer:

NISA [10]2 years ago

4 0

Heya!!

For calculate velocity, lets applicate formula

$\boxed{d = v * t}$

Δ Being Δ

d = Distance = 3790 m

t = Time = 249 s

v = Velocity = ?

⇒ Let's replace according the formula and clear "v":

$\boxed{v= 3790\ m / 249\ s}$

⇒ Resolving

$\boxed{ v = 15,22 \ m/s }$

Result:

The velocity is 15,22 meters per second.

Good Luck!!

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A 15g bullet is fired horizontally into a 3kg block of wood suspended by a long cord. Assume that the bullet remains in the bloc

Varvara68 [4.7K]

Answer:

261.3 m/s

Explanation:

Mass of bullet=m=15 g= $\frac{15}{1000}=0.015 kg$

1 kg=1000g

Mass of block=M=3 kg

d=0.086 m

Total mass =M+m=3+0.015=3.015 kg

K.E at the time strike=Gravitational potential energy at the end of swing

$\frac{1}{2}(m+M)^2V^2=(m+M)gh$

Using g= $9.8m/s^2$

Substitute the values

$\frac{1}{2}(3.015)V^2=3.015\times 9.8\times 0.086$

$V^2=\frac{2\times 3.015\times 9.8\times 0.086}{3.015}$

$V=\sqrt{2\times 3.015\times 9.8\times 0.086}}$

$V=1.3m/s$

Velocity after collision=V=1.3 m/s

Velocity of block=v'=0

Using conservation law of momentum

$mv+Mv'=(m+M)V$

Using the formula

$0.015v+3(0)=3.015(1.3)$

$0.015v=3.015(1.3)$

$v^2=\frac{3.015(1.3)}{0.015}=261.3$

$v=261.3 m/s$

5 0

3 years ago

Observe and compare the forces acting on the turtle and the cat.

Pepsi [2]

Answer:

The forces are balanced on both animals because they are not moving

More importantly than not moving is not accelerating.

Explanation:

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2 years ago

Si pudieras viajar a la Luna:

Nostrana [21]

Answer:

i) Distancia, ii) La cinta métrica es impracticable.

Explanation:

i) El concepto físico que se construye únicamente del punto de salida y el punto de llegada a la Luna es el concepto de desplazamiento, definido como la distancia en línea recta de un punto en el espacio con respecto a un punto de referencia (la Tierra en este caso).

La distancia puede involucrar trayectorias curvilíneas entre los puntos mencionados.

ii) Por último, el uso de una cinta métrica es impracticable debido a la cantidad de material a utilizar y los efectos gravitacionales, electromagnéticos y mecánicos que inducen a una deflexión o una ruptura de esa cinta debido a la magnitud de la distancia entre las superficies del planeta y el satélite, respectivamente.

En este caso, es mejor utilizar la medición con tecnología láser, basadas en el fenómeno del electromagnetismo.

4 0

3 years ago

a transmission-line cable, of length 3 km, consists of 19 strands of identical copper conductors, each 1.5 mm in diameter. becau

Ivan

the resistance of the cable is 582.9 ohms

we are given the length of the cable which is 3 km, of 1.5 mm in, the diameter and resistivity of copper which is 1.72 m

The formula we are referring to for calculating the resistance of the cable is

R = ρl/A.

As there are 19 strands of copper conductors, so the resistance will be

R = 19( ρl/A)

Here ρ is the resisitivity = 1.72 , l is the length = 3(1+0.05)*10³3= 3150 m

A=pie/4(1.5 x 10⁻³)^2 =1.766 x 10⁻⁶ =1.766 x 10^-6

Substituting the values in the formula we get

R = 19 ( 1.72*3150 )/1.766 x 10⁻⁶

= 582.9 ohm

To know more about resistance refer to the linkhttps://brainly.com/question/14547003?referrer=searchResults.

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1 year ago

In an application, Germanium is

Zigmanuir [339]

Answer:

produce electronics

Explanation:

The uses of Germanium are recorded beneath: Germanium's principle use is to deliver strong state hardware, semiconductors and fiber optic frameworks. As a phosphor in fluorescent lights.

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3 years ago