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BartSMP [9]
3 years ago
5

Not sure if it went through last time. Please help asap!

Physics
2 answers:
Olin [163]3 years ago
8 0
The equation for force is F=ma. Because we have the value of mass (0.42 kg) and the acceleration (14.8 m/s^2), simply plug them into the equation for force to get
0.42 \times 14.8 = 6.22
The answer is 6.22 N because newtons are the unit used to measure force.
MrMuchimi3 years ago
3 0
Force = mass x acceleration .

Force = 0.43kg x 14.8m/s^2

=. 6.22 Newtons
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Law of motion that says for every action there is an equal and opposite
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Answer: Newton's third law

Formally stated, Newton's third law is: For every action, there is an equal and opposite reaction. The statement means that in every interaction, there is a pair of forces acting on the two interacting objects. The size of the forces on the first object equals the size of the force on the second object.

Explanation:

4 0
3 years ago
Read 2 more answers
1.
lyudmila [28]

Answer:

100m \div  \frac{9 \: m}{1sec}  = 11.11 \: sec \:

I guess you can round it to 11 seconds.

Explanation:

Going with a speed 9m/s means you are going 9 meters in each second.

If you are going 9 meters in second how many seconds will it take to 100 meters?

Visually;

9 meters - - - 1 second

100 meters - - - ?seconds.

When you write like this 9 times ?seconds equal to 100 meters time 1 second. (you probably know this but just in case)

So to find ?second you multiply 100meters by 1 and divide it by 9 whixh will give you 11.1111 seconds whixh again I believe you can round it to 11.

(Kind of a) Proof;

If 9m * ?sec = 100 m * 1 sec

you send 9 meters to other side.

?sec = (100 m * 1 sec) ÷ 9m

Hope it was clear and it helps! Please let me know if you have any questions.

7 0
3 years ago
How high can a body vertically thrown with a speed of 40m/s raise after 3 sec (neglecting air
Tcecarenko [31]

y = 75.9 m

Explanation:

y = -(1/2)gt^2 + v0yt + y0

If we put the origin of our coordinate system at the point where a body is launched, then y0 = 0.

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= -44.1 m + 120 m

= 75.9

5 0
2 years ago
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Answer: Using fuel that has a lower-than-specified fuel rating.

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Most likely, what causes the cylinder head temperature and engine oil temperature gauges to exceed their normal operating ranges is using fuel that has a lower-than-specified fuel rating. This can lead to detonation of the engine which is the tendency for the fuel to pre-ignite or auto-ignite in an engine's combustion chamber.The cylinder head and the engine oil are part of the automobile systems that helps in fuel combustion.

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3 years ago
In objects motion will not change is the force is acting on the object are blank
maks197457 [2]
An object in motion stays in motion while an object at rest stays at rest.
3 0
3 years ago
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