All categories

3 years ago

Not sure if it went through last time. Please help asap!

Physics

2 answers:

Olin [163]3 years ago

8 0

The equation for force is F=ma. Because we have the value of mass (0.42 kg) and the acceleration (14.8 m/s^2), simply plug them into the equation for force to get
$0.42 \times 14.8 = 6.22$
The answer is 6.22 N because newtons are the unit used to measure force.

MrMuchimi3 years ago

3 0

Force = mass x acceleration .

Force = 0.43kg x 14.8m/s^2

=. 6.22 Newtons

You might be interested in

If the pressure acting on a given sample of an ideal gas at constant temperature is tripled, what happens to the volume of the g

oee [108]

Answer:

Explanation:

According to Boyle's law for constant temperature of gas Pressure is inversely proportional to the volume of gas.

$PV=nRT$

$PV=constant$

$P\propto \frac{1}{V}$

if Pressure is tripled then

$P\times V_1=3P\times V_2$

$V_2=\frac{V_1}{3}$

Volume becomes one-third of original volume

7 0

3 years ago

Identify the procedure to determine a formula for self-inductance, or inductance for short. Using the formula derived in the tex

kompoz [17]

Answer:

L = 0.0319 H

Explanation:

Given that,

Number of loops in the solenoid, N = 900

Radius of the wire, r = 3 cm = 0.03 m

Length of the rod, l = 9 cm = 0.09 m

To find,

Self inductance in the solenoid

Solution,

The expression for the self inductance of the solenoid is given by :

$L=\dfrac{\mu_o N^2 A}{l}$

$L=\dfrac{4\pi\times10^{-7}\times(900)^{2}\times\pi(0.03)^{2}}{0.09}$

L = 0.0319 H

So, the self inductance of the solenoid is 0.0319 henries.

4 0

3 years ago

Why is it a good idea to extend your bare hand forward when you are getting ready to catch a fast-moving baseball?

qaws [65]

Answer:d

Explanation:

It is good to extend your bare hand forward when you are getting ready to catch a fast-moving ball so you can pull your hand back, increasing the time to slow the ball thus decreasing the force.

While catching impulse is being transferred to hands imparting great force, lowering hand would increase the time so that average force decreases and chances to drop the ball also decreases.

4 0

3 years ago

The distribution circuit of a residential power line is operated at 2000 V rms. This voltage must be reduced to 240 V rms for us

forsale [732]

Answer:

$N_p\approx3958$

Explanation:

In an ideal transformer the relationship between the voltages is proportional to the ratio between the number of turns of the windings. Thus:

$\frac{V_p}{V_s} =\frac{N_p}{N_s}$

Where:

$V_p=Voltage\hspace{3}in\hspace{3}primary\hspace{3}coil$

$V_s=Voltage\hspace{3}in\hspace{3}secondary\hspace{3}coil$

$N_p=Turns\hspace{3}on\hspace{3}primary\hspace{3}coil$

$N_s=Turns\hspace{3}on\hspace{3}secondary\hspace{3}coil$

So, solving for $N_p$

$N_p=N_s*\frac{V_p}{V_s} =475*\frac{2000}{240} =3958.333333\approx3958$

7 0

3 years ago

Consider two identical objects released from rest high above the surface of Earth. (Neglect air resistance for this question.)

Nadusha1986 [10]

The question is missing its alternatives. Here is the complete question.

Consider two identical objects released from rest high above the surface of Earth. In Case 1, the object is released from a height above the surface of Earth equal to 1 Earth radius, and we measure its kinetic energy just before it hits the Earth to be K1. In Case 2, the obejct is released from a height above the surface of Earth equal to 2 Earth radii and its kinetic energy just before it hits is K2.

1. Compare the kinetic energy of the two objects just before they hit the surface of the earth.

a) K2 = 2K1; b) K2 = 4K; c) K2 = (4/3)K1; d) K2 = (3/2)K1;

Answer: C) K2 = (4/3)K1

Explanation: As it is related to the gravity of the Earth, the potencial energy is: U(r)= - $\frac{G.Me.m}{r}$ + U₀

In this case, U₀=0, G is the universal gravitational constant, Me is the mass of Earth, m is the mass of the object and r is the distance between the center of the Earth and the object.

The potencial energy of an object of mass m on the surface of the Earth is:

Usurface = - $\frac{G.Me.m}{Re}$