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3 years ago

Give the chemical equation for the net reaction that occurs during the titration calcium iodate

Chemistry

1 answer:

Allushta [10]3 years ago

7 0

The balanced equation will be:
Ca(IO₃)₂(s) ⇄ Ca²⁺(aq) + 2 IO₃⁻(aq)
The Ksp equation will be:
Ksp = [Ca²⁺][IO₃⁻]²

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Isaac wants to make s'mores. He holds a marshmallow on a metal skewer over a fire. A few seconds later, the marshmallow is cooke

natita [175]

Answer:

Thermal energy in the form of heat moved from the fire to the skewer and marshmallow.

Explanation:

He holds a marshmallow on a metal skewer over a fire. A few seconds late, the marshmallow is cooked and the skewer feels warm.

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Why is copper (i) sulfate Cu2So4^-2? not copper (ii)?

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Can you discount alcohol in Texas?.

iragen [17]

According to TABC laws on alcohol use, it is illegal to sell alcohol in many places in texas thus no you can't discount alcohol in Texas.

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1 year ago

Identify the classification of milk a aerosol b solid emulsion c solid aerosol d foam e emulsion

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option (c) emulsion is the right answer

Emulsion is a classification of milk.

<h3>Describe an emulsion.</h3>

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Emulsions form as a result of the cleansing action of soaps.

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(iii) Disinfectants and antiseptics combine with water to generate emulsions.

(iv) The emulsification technique is utilized to create medications.

<h3>How is an emulsion created?</h3>

When two immiscible liquids, such as oil and water, are stirred together with an emulsifier—which might be a protein, phospholipid, or even a nanoparticle—emulsion is created.

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2 years ago

4. Find the pH at each of the following points in the titration of 25 mL of 0.3 M HF with 0.3 M NaOH. The Ka value is 6.6x10-4 a

yawa3891 [41]

Explanation:

Since HF is a weak acid, the use of an ICE table is required to find the pH. The question gives us the concentration of the HF.

HF+H2O⇌H3O++F−HF+H2O⇌H3O++F−

Initial0.3 M-0 M0 MChange- X-+ X+XEquilibrium0.3 - X-X MX M

Writing the information from the ICE Table in Equation form yields

6.6×10−4=x20.3−x6.6×10−4=x20.3−x

Manipulating the equation to get everything on one side yields

0=x2+6.6×10−4x−1.98×10−40=x2+6.6×10−4x−1.98×10−4

Now this information is plugged into the quadratic formula to give

x=−6.6×10−4±(6.6×10−4)2−4(1)(−1.98×10−4)−−−−−−−−−−−−−−−−−−−−−−−−−−−−√2x=−6.6×10−4±(6.6×10−4)2−4(1)(−1.98×10−4)2

The quadratic formula yields that x=0.013745 and x=-0.014405

However we can rule out x=-0.014405 because there cannot be negative concentrations. Therefore to get the pH we plug the concentration of H3O+ into the equation pH=-log(0.013745) and get pH=1.86

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