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Leni [432]
3 years ago
8

Which statement is true about the atoms in helium gas?

Chemistry
1 answer:
jasenka [17]3 years ago
5 0

Answer: The answer is they are not closely packed

Explanation: HOPE THIS HELPS!!

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A beaker with 1.60×102 mL of an acetic acid buffer with a pH of 5.000 is sitting on a benchtop. The total molarity of acid and c
stich3 [128]

Answer:

The pH will change 0.16 ( from 5.00 to 4.84)

Explanation:

Step 1: Data given

volume of acetic acid buffer = 160 mL

The total molarity of acid and conjugate base in this buffer is 0.100 M

A student adds 7.10 mL of a 0.460 M HCl solution to the beaker.

The pKa of acetic acid is 4.740

pH = 5.00

Step 2: Calculate concentration of acid

Consider x = concentration acid

Consider y = concentration conjugate base

x + y = 0.100

5.00 = 4.740 + log y/x

5.00 - 4.740 = log y/x

0.26 = log y/x

10^0.26 =1.82 = y/x

1.82 x = y

Since x+y = 0.100

x + 1.82 x = 0.100

2.82 x = 0.100

x =0.0355 M = concentration acid

Step 3: Calculate concentration of conjugate base

y = 0.100 - x

0.100 - 0.0355 =0.0645 M= concentration conjugate base

Step 4: Calculate moles of acid

Moles = volume * molarity

moles acid = 0.160 L * 0.0355 M= 0.00568  moles

Step 5: Calculate moles of conjugate base

moles conjugate base = 0.0645 M * 0.160 L=0.01032 moles

Step 6: Calculate moles HCl

moles HCl = 7.10 * 10^-3 L * 0.460 M=0.003266 moles

Step 7: Calculate new moles

A- + H+ = HA

moles conjugate base = 0.01032 - 0.003266 =0.007054  moles

moles acid = 0.00568 + 0.003266=0.008946 moles

Step 8: Calculate the total volume

total volume = 160 + 7.10 = 167.1 mL = 0.1671 L

Step 9: Calculate the concentration of the acid

concentration acid = 0.008946/ 0.1671 =0.0535 M

Step 10: Calculate the concentration of conjugate base

concentration conjugate base = 0.007054/ 0.1671 =0.0422 M

Step 11: Calculate the pH

pH = 4.740 + log 0.0535/ 0.0422=4.84

change pH = 5.00 - 4.84=0.16

The pH will change 0.16

5 0
3 years ago
IF ANSWER I WILL GIVE BRAINLESS
vovikov84 [41]

Answer:

Answer 9 - 100 joules energy was at the producer level

Answer 10 - Remaining energy is used in metabolism

Explanation:

Answer 9

The energy at each trophic level is only 10% of the energy at its previous trophic level.

The energy at producer level is X

10 % of X = 10 Joules

\frac{10}{100} * X = 10\\X = 100Joules

Answer 10

Because the remaining 90% energy is utilized by the producer for its metabolism

3 0
3 years ago
In the equation. C + O2 --------> CO2; CO2 is the
lubasha [3.4K]

Answer: Product

Explanation:

A Chemical reaction shows how substances, written in symbols  known as  reactants, are converted to different substances called products. An arrow from the left hand side (reactants) points to right hand side ( products )shows the direction of  flow of reaction.

In the equation. C + O2 --------> CO2

                             reactant------> product

CO2  is the product

7 0
3 years ago
If parents wanted to pick their child's traits like hair color, gender, eye color, what would doctors have to do?
kap26 [50]

Answer:

Nothing

Explanation:

I would say this because the parents are picking the baby's traits and they make all the decisions. And i guess the doctor would have to follow the traits, if i'm right  i tried

5 0
3 years ago
When solving an equation using Gay-Lussac's law, which of the following steps do not apply? A. List your knowns and unknowns. B.
suter [353]

Answer:

C. Plug the unknowns into the ideal gas law formula.

Explanation:

Gay-Lussac's law states that:

"For a constant mass of an ideal gas kept at constant volume, the pressure of the gas is directly proportional to its absolute temperature"

Mathematically, it can be written as:

\frac{p_1}{T_1}=\frac{p_2}{T_2}

where

p1 is the initial pressure

T1 is the initial temperature (in Kelvin)

p2 is the final pressure

T2 is the final temperature (in Kelvin)

Therefore, in order to solve for one of the 4 variables, the following steps must be adopted:

A. List your knowns and unknowns.

B. Convert temperature to kelvin.

D. Solve for the unknown.

While the following step is not needed:

C. Plug the unknowns into the ideal gas law formula.

Because we do not need to use the ideal gas law formula.

8 0
3 years ago
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