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Lynna [10]
3 years ago
6

I am the weight of the atom, I can tell you how many neutrons there are in an atom

Chemistry
1 answer:
andrew-mc [135]3 years ago
8 0

Answer:

Atomic Mass?

Explanation:

You might be interested in
Which is an example of an atom?
xenn [34]
It is A)The smallest unit of Ne 

5 0
4 years ago
A 15.0 L tank of gas contained at a high pressure of 8.20 • 10^4 torr. The tank is opened and the gas expands into an empty cham
Kay [80]

Answer:

P₂ = 0.205torr

Explanation:

Boyle's law relates the pressure and volume of a gas under two different conditions. The equation is:

P₁V₁ = P₂V₂

<em>Where P is pressure and V volume of of 1, initial conditions and 2, final conditions.</em>

P₂ is our incognite

Replacing:

P₁V₁ = P₂V₂

8.20x10⁴torr*15.0L = P₂*600x10⁴L

<h3>P₂ = 0.205torr</h3>

<em />

4 0
3 years ago
What is the Pauli Exclusion Principle?
Fiesta28 [93]

Answer:

the answer is A An atomic orbital can only hold a maximum of 2 electrons, each with opposite spins

Explanation:

3 0
3 years ago
The electron configuration for carbon is:
seropon [69]

Answer:

1 {s}^{2} 2 {s}^{2} 2 {p}^{2}

Or

[He] 2s2 2p2

Explanation:

Stay safe, stay healthy and blessed

Have a good day!

Thank you

5 0
2 years ago
The mole fraction of CO2 in a certain solution with H2O as the solvent is 3.6 × 10−4. What is the approximate molality of CO2 in
nataly862011 [7]

Answer: C) 0.020 m

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

Molality=\frac{n\times 1000}{W_s}

where,

n = moles of solute  

W_s = weight of solvent in g  

Mole fraction of CO_2 is = 3.6\times 10^{-4} i.e.3.6\times 10^{-4}  moles of CO_2 is present in 1 mole of solution.

Moles of solute (CO_2) = 3.6\times 10^{-4}

moles of solvent (water) = 1 - 3.6\times 10^{-4} = 0.99

weight of solvent =moles\times {\text {Molar mass}}=0.99\times 18=17.82g

Molality =\frac{3.6\times 10^{-4}\times 1000}{17.82g}=0.020

Thus  approximate molality of CO_2 in this solution is 0.020 m

5 0
4 years ago
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