We are given the functions:
<span>S (p) = 40 + 0.008 p^3 --->
1</span>
<span>D (p) = 200 – 0.16 p^2 --->
2</span>
T o find for the price in which the price of supply equals
demand, all we have to do is to equate the two equations, equation 1 and 2, and
calculate for the value of p, therefore:
S (p) = D (p)
40 + 0.008 p^3 = 200 – 0.16 p^2
0.008 p^3 + 0.16 p^2 = 160
p^3 + 20 p^2 = 20,000
p^3 + 20 p^2 – 20,000 = 0
Calculating for the roots using the calculator gives us:
p = 21.86, -20.93±21.84i
Since price cannot be imaginary therefore:
p = 21.86
Answer:
n = 5, -6
Step-by-step explanation:
Ur welcome
(13x+14)(6x-5)=0
78x²-65x+84x-70=0
78x²+19x-70=0
It was equation.
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Factoring⇒ a×c=78×(-70)=-5460
84×(-65)=-5460
84+(-65)=19 which is b
__________________
78x²+84x-65x-70=0
6x(13x+14)-5(13x+14)=0
(13x+14)(6x-5)=0
13x+14=0 6x-5=0
13x=-14 6x=5
x=-14/13 x=5/6
Two solution X=-14/13;5/6
Answer: 14+x=17
Step-by-step explanation:
when you do this you can put whatever letter you want but sum is adding so this is why it came out as it did
Answer:
a
Step-by-step explanation:
