Don't go by my answers pls

Write the equations of the lines with the following descriptions

Romashka [77]

Answer: Y= -2/3x -3

Explanation: The formula is y-y1=m(x+b).
Fill in what we know, which is,
y-(-5)=-2/3 (x-3) Then you distribute and get y+5=-2/3x+2. Then you subtract 5 from each side and get your final answer of y=-2/3x -3

4 0

3 years ago

5) To find the slope of the trend line below, Riley chose the points (1, 35) and (2, 25).

avanturin [10]

The slope of the trend line is -10

4 0

3 years ago

The results of a mathematics placement exam at two different campuses of Mercy College follow: Campus Sample Size Sample Mean Po

Leona [35]

Answer:

$z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37$

$p_v =P(Z>3.37)=1-P(Z$

Comparing the p value with a significance level for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.

Step-by-step explanation:

Data given

Campus Sample size Mean Population deviation

1 330 33 8

2 310 31 7

$\bar X_{1}=33$ represent the mean for sample 1

$\bar X_{2}=31$ represent the mean for sample 2

$\sigma_{1}=8$ represent the population standard deviation for 1

$\sigma_{2}=7$ represent the population standard deviation for 2

$n_{1}=330$ sample size for the group 1

$n_{2}=310$ sample size for the group 2

$\alpha$ Significance level provided

z would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean for Campus 1 is higher than the mean for Campus 2, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}\leq 0$

Alternative hypothesis: $\mu_{1} - \mu_{2}> 0$

We have the population standard deviation's, and the sample sizes are large enough we can apply a z test to compare means, and the statistic is given by:

$z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37$

P value

Since is a one right tailed test the p value would be:

$p_v =P(Z>3.37)=1-P(Z$

Comparing the p value with a significance level for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.

5 0

3 years ago

the cubic polynomial f(x) is such that the coefficient of x cube is -1 and the roots of the equation f(x)=0 are 1, 2 & k.Giv

77julia77 [94]

The polynomial function is a cubic polynomial function with a general equation of y = ax^3 + bx^2 + cx + d. a is given to be -1. roots make y = 0

when x = 1
y = -1(1) + b + c + d = -1 +b+c+d = 0
when x = 2
y = -1*8 + 4b + 2c + d = -8 + 4b+c+d = 0
when x =k
y = -k^3 + k^2b + kc + d = 0

when x = 3, y =8
8 = -27 + 9b + 3c + d

b=7/3 , c=23/3 , d=−9
k1 = 9.3556
k2 = -2.71051
k3 = 0.35491

3 0

4 years ago

Please help me with this math problem!! Will give brainliest!! :)

lora16 [44]

Answer:

$2x^3-3x^2-10x+15\\$

Step-by-step explanation:

To find (fg)(x), we have to look at f(x) and g(x) and multiply the two quantities together. We are already given the two quantities individually so all that is left is the multiplication:

$(fg)(x)=(-2x+3)(5-x^2)=-10x+2x^3+15-3x^2\\$

If we reorder the terms to go from highest degree to lowest, we get our final answer to be the following:

$2x^3-3x^2-10x+15$

6 0

1 year ago