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tamaranim1 [39]
4 years ago
11

Describe how transverse waves can be produced by a rope. Then describe hiw pieces of the rope move as waves pass.

Physics
1 answer:
Oduvanchick [21]4 years ago
3 0
We did this experiment before, when the rope moves, it represents the waves passing through in from the level of intensity. I hope this is a good answer.
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Which refers to a material that causes a wave to bounce off of it?
ale4655 [162]

Answer:

the answer to the question is a reflector

7 0
3 years ago
Does an object need a force to start moving
nadya68 [22]
Newton's first law actually states that a force isn't needed to keep an object moving, so no.
8 0
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What does the number or density of field lines on the source charge indicate
7nadin3 [17]

Answer:

The strength of the field

Explanation:

The density of field lines of a field (e.g. gravitational field, or electric field) indicates the strength or magnitude of the field itself. In particular:

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- The regions where the field lines are more spread apart (less dense) are the regions where the field is weaker

For example, if we consider the electric field generated by a positive point charge, the electric field is radial (outwards from the charge) and the spacing between the lines increases as we move away from the charge: this means that the strength of the field increases as we move away from the charge.

4 0
3 years ago
A sample of a gas in a rigid container at 30. 0°c and 2. 00 atm has its temperature increased to 40. 0°c. What will be the new p
Diano4ka-milaya [45]

Answer:

2.066 atm

Explanation:

PV = nRT      increase T    volume and n and R remain constant

30 C = 303.15 K      40 C = 313.15

P  prop to T      new P   will be   313.15/303.15 * 2 atm = 2.066 atm

8 0
2 years ago
Una bombilla de incandescencia tiene un filamento de wolframio cuya resistividad es de 5,6 por 10 a la -8 m , su longitud es de
Amanda [17]

Answer:

  R = 0.14  Ω

Explanation:

The resistance of a metal is given by the relation

         R = \rho \frac{L}{A}

where ρ the resistivity is 5.6 10-8 Ω m, they also give the length and the cross section (area)

Let's reduce the magnitudes to the SI system

        L = 200cm (1m / 100cm) = 2.00m

        A = 8.0 10⁻⁷ m²

let's calculate

       R = 5.6 10⁻⁸  \frac{2.00}{8.0  \ 10^{-7} }

       R = 1.4 10⁻¹ Ω

       R = 0.14  Ω

5 0
3 years ago
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