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Burka [1]
3 years ago
5

You and a friend each drive 50 km to the same destination. You travel at 88.5 km/h and your friend at 94.5 km/h. How long will y

our friend wait for you at the end of the trip
Physics
1 answer:
ANTONII [103]3 years ago
4 0

Answer:

your friend will wait for you for 2.2 minutes.

Explanation:

Given;

Distance of the journey, d = 50 km

your speed, v₁ = 88.5 km/h

your friends speed, v₂ = 94.5 km/h

The time taken before you reached the end of the trip;

time = \frac{distance }{speed} \\\\t_1 = \frac{d}{v_1} \\\\t_1 = \frac{50}{88.5} \\\\t = 0.565 \ hour

The time taken before your friend reached the end of the trip;

time = \frac{distance }{speed} \\\\t_2 = \frac{d}{v_2} \\\\t_2 = \frac{50}{94.5} \\\\t = 0.529 \ hour \\\\

The difference in time = (0.565 - 0.529) hour

                                     = 0.036 hour

                                     = 0.036 x 60 min

                                     = 2.2 mins

Therefore, your friend will wait for you for 2.2 minutes.

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A plane flies from base camp to lake a, 200 km away in the direction 20.0° north of east. after dropping off supplies it flies t
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Distance of lake a is 200 km at 20 degree north of east

distance between lake a and b is 230 km at 30 degree west of north

now the distance between base and lake b is given as

d = d_1 + d_2

given that

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d_1 = 187.94 i + 68.4 j

d_2 = -230 sin30 i + 230 cos30 j

d_2 = -115 i + 199.2 j

now the total distance is

d = (187.94 - 115)i + (199.2 + 68.4)j

d = 72.94 i + 267.6 j

now the magnitude of the distance is given as

d = \sqrt{72.94^2 + 267.6^2}

d = 277.4

also the direction is given as

\theta = tan^{-1}\frac{267.6}{72.94}

\theta = 74.7 degree

<em>so it is 277.4 km at 74.7 degree North of East</em>

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Answer:

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