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Burka [1]
3 years ago
5

You and a friend each drive 50 km to the same destination. You travel at 88.5 km/h and your friend at 94.5 km/h. How long will y

our friend wait for you at the end of the trip
Physics
1 answer:
ANTONII [103]3 years ago
4 0

Answer:

your friend will wait for you for 2.2 minutes.

Explanation:

Given;

Distance of the journey, d = 50 km

your speed, v₁ = 88.5 km/h

your friends speed, v₂ = 94.5 km/h

The time taken before you reached the end of the trip;

time = \frac{distance }{speed} \\\\t_1 = \frac{d}{v_1} \\\\t_1 = \frac{50}{88.5} \\\\t = 0.565 \ hour

The time taken before your friend reached the end of the trip;

time = \frac{distance }{speed} \\\\t_2 = \frac{d}{v_2} \\\\t_2 = \frac{50}{94.5} \\\\t = 0.529 \ hour \\\\

The difference in time = (0.565 - 0.529) hour

                                     = 0.036 hour

                                     = 0.036 x 60 min

                                     = 2.2 mins

Therefore, your friend will wait for you for 2.2 minutes.

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Suppose you exert a force of 180 N tangential to a 0.280-m-radius 75.0-kg grindstone (a solid disk). What is the angular acceler
Lina20 [59]

Explanation:

It is given that,

Force on grindstone, F = 180 N

Radius of grindstone, r = 0.28 m

Mass of grindstone, m = 75 kg

We need to find the angular acceleration of the grindstone. In rotational motion, the relation between the torque and angular acceleration is given by :

\tau=I\times \alpha

\alpha=\dfrac{\tau}{I}

I is the moment of inertia of solid disk, I=\dfrac{1}{2}mr^2

\tau is the torque exerted, \tau=F\times r

\alpha=\dfrac{F\times r}{\dfrac{1}{2}mr^2}

\alpha=\dfrac{2F}{mr}

\alpha=\dfrac{2\times 180\ N}{75\ kg\times 0.28\ m}

\alpha =17.14\ rad/s^2

So, the angular acceleration of the disk is 17.14\ rad/s^2. Hence, this is the required solution.

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3 years ago
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Electric charges that are different attract each other.
n200080 [17]

There are two forces between any two charges
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An aluminum calorimeter with a mass of 100 g contains 250 g of water. The calorimeter and water are in thermal equilibrium at 10
Nadya [2.5K]

Answer:

1822.14 J/kg C

Explanation:

Mass of aluminum  = 0.100 kg

Mass of Water = 0.250 kg

Mass of copper = 0.300 kg

Mass of unknown object = 0.70 kg

Initial temperature of Aluminum = 10 C

Initial  temperature  of water = 10 C

Initial temperature of copper = 30 C

Initial temperature of = 100 C

Final temperature of all substances = 20 C

Change in temperature of each  of them Aluminum, water , copper and unknown material  respectively = 10 C , 10 C , -10 C, -80 C respectively

Specific heat of  each  of them Aluminum, water , copper and unknown material  respectively = 900,4186,387 and c respectively.

Heat gained by aluminum and water = (0.1)(900)(10) + (0.250)(4186)(10) = 11365 j

heat lost by copper and unknown  material  =(0.3)(387)(-10) = -1161

heat lost by unknown  material  =  (0.070)(c)(-80) = -5.6 c

Now solve for c using the calorimetry principle.

Heat lost + Heat gained = 0

⇒ -5.6 c = -11365 - (-1161) = -10204 j

Specific heat of unknown material = - 10204 / -5.6

                                                         = 1822.14  j/kg C  

b) Material having a specific heat of 1800 j /kg C is

Polyurethane elastomer.

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