Question

A point charge is placed 3 m from a 4 uC charge. What is the strength of the electric field on the point charge at this

Answer 1

Answer:

$4,000N/C$

Explanation:

the information we have is:

distance:  $r=3m$

charge: $q= 4\mu C$

since the prefix $\mu$ is equal to $1x10^{-6}$

the charge is: $q=4x10^{-6}C$

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To calculate the strength of the electric field we use the following formula:

$E=\frac{kq}{r^2}$

where $q$ is the charge, $r$ is the distance and $k$ is Coulomb's constant

$k=9x10^9Nm^2/C^2$

substituting all the known values into the formula:

$E=\frac{(9x10^9Nm^2/C^2)(4x10^{-6}C)}{(3m)^2} \\E=\frac{36,000Nm^2/C}{9m^2} \\E=4,00N/C$

The strength of the electric field on the point charge at the distance of 3m is 4,000 N/C.

Answer 2

Answer:4000v/m

Explanation: