To solve this problem it is necessary to apply the concepts related to Newton's second Law and the force of friction. According to Newton, the Force is defined as
F = ma
Where,
m= Mass
a = Acceleration
At the same time the frictional force can be defined as,

Where,
Frictional coefficient
N = Normal force (mass*gravity)
Our values are given as,

By condition of Balance the friction force must be equal to the total net force, that is to say



Re-arrange to find acceleration,



Therefore the acceleration the horse can give is 
Its called the "westerly"
The rate at which the height is changing is ( 5 / x ) m / hr
We know that,
Area of an equilateral triangle A =
/ 4
h =
x / 2
Where,
x = Side
h = Height
Given that,
dA / dt = 5
/ hr
h =
x / 2
Differentiate both sides with respect to t
dh / dt = (
/ 2 ) ( dx / dt )
dx / dt = ( 2 /
) ( dh / dt )
A =
/ 4
Differentiate both sides with respect to t
dA / dt = (
/ 4 ) ( 2x ) ( dx / dt )
5 = (
/ 4 ) ( 2x ) ( 2 /
) ( dh / dt )
dh / dt = ( 5 / x ) m / hr
Rate of change of height is defined as the rate at which height of an object changes with respect to time. It is represented as dh / dt
Therefore, the rate at which the height is changing is ( 5 / x ) m / hr
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Answer:
none of the above
Explanation:
im pretty positive this is the answer tell me if i am wrong please