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Fed [463]
3 years ago
6

Can someone help me with this but give details please? (it's a physics class)​

Physics
1 answer:
tino4ka555 [31]3 years ago
5 0

Answer:

The question is basically asking you to research a instrument that provides scientific-physical terms like sound waves. It also says to explain how different types of instruments provide different tones.(Hint: Sound waves)

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A transmission system at a radio station uses a/an _______ to convert a direct current into a high frequency alternating current
Vinvika [58]
A transmission system at a radio station uses an oscillator to convert a direct current into a high frequency alternating current. Direct current or DC is the current in which the flow of the charge is one directional. In case of alternating current or AC, the flow of the charge reverses direction after a period of time.
<span>In regards to the second question, a unit for measuring frequency is the hertz. So the correct answer to the given question is option “B”. </span>



5 0
4 years ago
Read 2 more answers
A+10 u charge and a -10 4C (1 HC - 106 C), at a distance of 0.3 m,
Marina CMI [18]

Answer:

B. Attract each other with a force of 10 newtons.

Explanation:

Statement is incorrectly written. <em>The correct form is: A </em>+10\,\mu C<em> charge and a </em>-10\,\mu C<em> at a distance of 0.3 meters. </em>

The two particles have charges opposite to each other, so they attract each other due to electrostatic force, described by Coulomb's Law, whose formula is described below:

F = \frac{\kappa \cdot |q_{A}|\cdot |q_{B}|}{r^{2}} (1)

Where:

F - Electrostatic force, in newtons.

\kappa - Electrostatic constant, in newton-square meters per square coulomb.

|q_{A}|,|q_{B}| - Magnitudes of electric charges, in coulombs.

r - Distance between charges, in meters.

If we know that \kappa  = 8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}}, |q_{A}| = |q_{B}| = 10\times 10^{-6}\,C and r = 0.3\,m, then the magnitude of the electrostatic force is:

F = \frac{\kappa \cdot |q_{A}|\cdot |q_{B}|}{r^{2}}

F = 9.987\,N

In consequence, correct answer is B.

4 0
3 years ago
A horizontal 791-N merry-go-round is a solid disk of radius 1.56 m and is started from rest by a constant horizontal force of 49
ICE Princess25 [194]

Answer:

K.E=273.5J

Explanation:

Given data

F_{g}=791N\\F_{h}=49N\\r=1.56m\\t=3.03s

To find

Kinetic Energy

Solution

The moment of inertia is given as:

I=(\frac{1}{2} )MR^2\\I=\frac{1}{2}(F_{g}/g)R^2\\ I=\frac{1}{2}(\frac{791N}{9.8m/s^2} )(1.56m)^2\\ I=98.21kg.m^2

The angular acceleration is given as:

\alpha =\frac{T}{I}\\\alpha  =\frac{F_{y}R}{I}\\ \alpha =\frac{(49N)(1.56m)}{98.2kg.m^2}\\\alpha  =0.778rad/s^2

Now the angular velocity is given by:

w=\alpha t\\w=(0.778rad/s^2)(3.03s)\\w=2.36rad/s

So the kinetic energy given as:

K.E=(\frac{1}{2} )Iw^2\\K.E=\frac{1}{2}(98.21kg.m^2)(2.36rad/s)^2\\ K.E=273.5J

8 0
3 years ago
A tsunami is a large wave that is caused by
marysya [2.9K]
An earthquake or disturbance undersea.


~ThePirc
5 0
3 years ago
Read 2 more answers
acontainer is filled whith mercury to alevel of 10m whit water to alevel of 8m and whit oil to alevel of 5m the densities oil ,w
Alborosie

Answer:

1450.4 KNm^{2}

Explanation:

Pressure = ρhg

where: ρ is the density of the liquid, h is the height and g the force of gravity.

Total pressure exerted by the liquids at the base = Pressure of oil + Pressure of water + Pressure of mercury

So that,

i. Pressure of oil = ρhg

(ρ = 0.8 g/cm³ = 800 kg/m³)

                        = 800 x 5 x 9.8

                        = 39200

Pressure of oil = 39200 Nm^{2}

ii. Pressure of water = ρhg

(ρ = 1 g/cm³ = 1000 kg/m³)

                                      = 1000 x 8 x 9.8

                                     = 78400

Pressure of water = 78400 Nm^{2}

ii. Pressure of mercury = ρhg

(ρ = 13.6 g/cm³ = 13600 kg/m³)

                      = 13600 x 10 x 9.8

                      = 1332800

Pressure of mercury = 1332800 Nm^{2}

So that,

Total pressure exerted by the liquids at the base = 39200 + 78400 + 1332800

                                               = 1450400

                                               = 1450.4 KNm^{2}

Total pressure exerted by the liquids at the base is 1450.4 KNm^{2}.

8 0
3 years ago
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