It will cause the top speed to decrease because it makes the car have more wind resistance
Answer: A train traveling initially at 16 m/s is under constant acceleration of 2 m/2. At a distance of 720m it will travel in 20 s, and the final velocity will be 56m/s.
Explanation: To find the answer, we need to know about uniformly accelerated motion.
<h3>
How to solve the problem?</h3>
![u=16m/s\\a=2 m/s^2\\t=20s](https://tex.z-dn.net/?f=u%3D16m%2Fs%5C%5Ca%3D2%20m%2Fs%5E2%5C%5Ct%3D20s)
- We have to find the distance travelled by the train.
![S=ut+\frac{1}{2}at^2](https://tex.z-dn.net/?f=S%3Dut%2B%5Cfrac%7B1%7D%7B2%7Dat%5E2)
- Substituting values, we get,
![S=(16*20)+\frac{2*20^2}{2} =720 m.](https://tex.z-dn.net/?f=S%3D%2816%2A20%29%2B%5Cfrac%7B2%2A20%5E2%7D%7B2%7D%20%3D720%20m.)
- We have the equation for final velocity as,
![v^2=u^2+2aS\\thus,\\v=\sqrt{u^2+2aS} =\sqrt{16^2+(2*2*720)} =56 m/s.](https://tex.z-dn.net/?f=v%5E2%3Du%5E2%2B2aS%5C%5Cthus%2C%5C%5Cv%3D%5Csqrt%7Bu%5E2%2B2aS%7D%20%3D%5Csqrt%7B16%5E2%2B%282%2A2%2A720%29%7D%20%3D56%20m%2Fs.)
Thus, we can conclude that, a train traveling initially at 16 m/s is under constant acceleration of 2 m/2. At a distance of 720m it will travel in 20 s, and the final velocity will be 56m/s.
Learn more about the uniformly accelerated motion here:
brainly.com/question/28105762
#SPJ4
Answer:
4.87×10⁶ kJ
1.63×10⁸ Joules
1015 $
Explanation:
a. To convert the units, you can use this conversion factor:
1 kWh = 3.6×10⁶J
1355 kWh . 3.6×10⁶J / 1 kWh = 4.871×10⁹ J
Now we convert to kJ → 4.87×10⁹ J . 1 kJ/1000J = 4.87×10⁶ kJ
b. In 30 days, we used 1355 kWh so, let's determine the use by day
1355 kWh / 30 day = 45.2 kWh
Now we convert the 45.2 kWh to Joules → 45.2 kWh . 3.6×10⁶J / 1 kWh =
1.63×10⁸ Joules
c. We can make a rule of three, for this:
1 kWh costs $0.749
1355 kWh will pay (1355 . 0.749) / 1 = 1015 $
Answer:
The answer is B complimentary
Explanation: