Answer: 9m
Explanation:
Our given:
Acceleration- 5m/s^2
Time- 3.6 seconds
Use the equation d = 1/2 • a • t^2
d = 1/2 • 5m/s^2 • 3.6 secs
d = 2.5m/s^2 • 3.6 secs
d = 9m
I hope this is correct
Answer:
the difference between a charged body is an body that has either a surplus or deficiency of electrons, and is negatively and positively charged respectively. And the difference between an uncharged body is that it’s a 'neutral' body that has an equal number of protons and electrons.
Explanation:
This question involves the concepts of work done and elastic potential energy.
The work done by the spring when its extension changes from X to X/4 is "0.56 E".
The work done by the spring is equal to the elastic potential energy stored in the spring, which is given as follows:

where,
W = work done = ?
E = elastic potential energy
k = spring constant
X = extension
Now, the spring moves to an extension of X/4, so the change in extension will be:

Hence, the work done will become:

<u>W = 0.56 E</u>
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Learn more about Elastic Potential Energy here:
brainly.com/question/156316?referrer=searchResults
Attached picture shows Elastic Potential Energy.
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