Question

A car is moving at 10 m/s to the right. It accelerates for 10 s after which it is moving at 5 m/s to the left. What was the car's acceleration during the 10 s interval? (a)-1.5 m/s^2 (b) -0.5 m/s^2 (c) 9.8 m/s^2 (d) 0.5 m/s^2 (e) 1.5 m/s^2

Answer 1

Answer:

Acceleration, $a=-1.5\ m/s^2$

Explanation:

It is given that,

Initial velocity of the car, u = 10 m/s (in right)

Final velocity of the car, v = -5 m/s (in left)  

Time taken, t = 10 s

Let a is the acceleration of the car. It can be calculated using the equation of kinematics. The equation is as :

$v=u+at$

$a=\dfrac{v-u}{t}$

$a=\dfrac{-5-10}{10}$    

$a=-1.5\ m/s^2$

So, the acceleration of the car is $-1.5\ m/s^2$. Hence, this is the required solution.