The diagonals intersect perpendicularly, two consecutive angled are supplementary, and that opposite angles are equal
Answer:
the mode is 7 because they have the most points
Step-by-step explanation:
Make a box putt the 70% at the top on the ouside then sub 100%-70% the box should have 4 squares so then on the bottom of the box on the outside. it should be 30% then in the top left corner put 28 and under it 46 then do
46/28 × 70% over 1 see if that helps
Answer:
The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of 
.
Step-by-step explanation:
The formula from the maximum distance of a projectile with initial height h=0, is:
Where 
is the initial velocity.
In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is ![[0, \pi/2]](https://tex.z-dn.net/?f=%5B0%2C%20%5Cpi%2F2%5D)
. The critical points of the function are those who make 
:
The critical value inside the interval is .
The second step is to find the values of the function at the endpoints of the interval:
The biggest value of f is gived by , therefore is the absolute maximum.
In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of .
Answer:
86 cm²
Step-by-step explanation:
Ok, so since 4 circles fit in the square, each circle's diameter must be 10.
Which means the radius of each circle is 5 because 10 ÷ 2 = 5.
Now we can solve for area.
A = πr²
A = 3.14 x 5²
A = 3.14 x 25
A = 78.5 cm²
78.5 cm² is the area of one circle so we multiply that by 4.
78.5 x 4 = 314 cm²
Now we subtract from the area of the square.
20 x 20 = 400 cm²
400 - 314 = 86 cm²
