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Anettt [7]
3 years ago
6

aluminum bronze contains 92.0% of copper and 8.0% aluminum. what maximum mass of aluminum bronze can be prepared from 73.5g of c

opper and 42.2g of aluminum?
Chemistry
1 answer:
slega [8]3 years ago
4 0
The answer is 79.9 g.

Copper takes 92.0% of aluminum bronze and it is a limiting factor. We have aluminum in excess, so we need to make a proportion.
If 73.5 g of copper are 92.0%, how many g of aluminum bronze will be 100%:
73.5 g : 92.0% = x : 100%.
x = 73.5 g : 100% * 92.0%
x = 79.9 g

Therefore, from 73.5 g of copper and 6.4 g of aluminum (since 79.9 g - 73.5 g = 6.4 g), maximum 79.9 g of aluminum bronze can be prepared.
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which of the following cannot be considered a single phase? a) a pure solid b) a pure liquid c) a homogeneous mixture d) a heter
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Alex17521 [72]

Answer:

2 AsCl₃ + 3 H₂S → As₂S₃ + 6 HCl

Explanation:

When we balance a chemical equation, what we are trying to do is to achieve the same number of atoms for each element on both sides of the arrow. On the right of the arrow is where we can find the products, while the reactants are found on the left of the arrow.

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AsCl₃ + H₂S → As₂S₃ +HCl

<u>reactants</u>

As --- 1

Cl --- 3

H --- 2

S --- 1

<u>products</u>

As --- 2

Cl --- 1

H --- 1

S --- 3

2 AsCl₃ + H₂S → As₂S₃ +HCl

<u>reactants</u>

As --- 2

Cl --- 6

H --- 2

S --- 1

<u>products</u>

As --- 2

Cl --- 1

H --- 1

S --- 3

The number of As atoms is now balanced.

2 AsCl₃ + 3 H₂S → As₂S₃ +HCl

<u>reactants</u>

As --- 2

Cl --- 6

H --- 6

S --- 3

<u>products</u>

As --- 2

Cl --- 1

H --- 1

S --- 3

The number of S atoms is now equal on both sides.

2 AsCl₃ + 3 H₂S → As₂S₃ + 6 HCl

<u>reactants</u>

As --- 2

Cl --- 6

H --- 6

S --- 3

<u>products</u>

As --- 2

Cl --- 6

H --- 6

S --- 3

The equation is now balanced.

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2 years ago
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vlabodo [156]
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