<u>Answer</u>:-
Try this formula:
W= Fd
F = W by d
Explanation:-
(Note: A newton-meter is the same thing as a joule, so the units for work are the same as those for energy – joules).
A. The gas will diffuse from the more concentrated are to the least concentrated.
Explanation:
From the question it can be infered that initially only parent atoms were present in the rock and no daughter atom. So, initially there was only uranium atom and no lead atom. So, in total there were 500+1500= 2000 uranium atom. And no lead tom was there.
Answer:
![\boxed {\boxed {\sf 53, 346 \ Joules}}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Cboxed%20%7B%5Csf%2053%2C%20346%20%5C%20Joules%7D%7D)
Explanation:
We are given the specific heat and change in temperature, so we should use this heat formula:
![q=m C \Delta T](https://tex.z-dn.net/?f=q%3Dm%20C%20%5CDelta%20T)
where m is the mass, C is the specific heat capacity, and ΔT is the change in temperature.
We know the mass is 150 grams. The specific heat of water is 4.184 J/g °C.
Let's find the change in temperature.
Subtract the initial temperature from the final temperature.
- ΔT= final temp - initial temp
- final= 95.0 °C and initial= 10.0 °C
- ΔT= 95.0 °C - 10.0 °C= 85.0 °C
Now we know all the values:
![m= 150 \ g \\C= 4.184 J/ g \ \textdegree C \\\Delta T= 85.0 \textdegree C](https://tex.z-dn.net/?f=m%3D%20150%20%5C%20g%20%5C%5CC%3D%204.184%20J%2F%20g%20%5C%20%20%5Ctextdegree%20C%20%5C%5C%5CDelta%20T%3D%2085.0%20%5Ctextdegree%20C)
Substitute them into the formula.
![q=(150 \ g) (4.184 \ J/g \ \textdegree C)(85.0 \textdegree C )](https://tex.z-dn.net/?f=q%3D%28150%20%5C%20g%29%20%284.184%20%5C%20J%2Fg%20%5C%20%5Ctextdegree%20C%29%2885.0%20%5Ctextdegree%20C%20%29)
Multiply all three numbers together. Note that the grams (g) and degrees Celsius (°C) will cancel out. Joules (J) will be the only remaining unit.
![q=(627.6 \ J/ \textdegree C) ( 85.0 \textdegree C)](https://tex.z-dn.net/?f=q%3D%28627.6%20%5C%20J%2F%20%5Ctextdegree%20C%29%20%28%2085.0%20%5Ctextdegree%20C%29)
![q=53346 \ J](https://tex.z-dn.net/?f=q%3D53346%20%5C%20J)
<u>53,346 Joules</u> of heat are required.
1) State the balanced chemical equation
Na3 PO4 + 3 AgNO3 → 3NaNO3 + Ag3 PO4
sodium phosphate silver nitrate sodium nitrate silver phosphate
2) State the molar ratios
1 mol Na3PO4 : 3 mol AgNO3 : 3 mol NaNO3 : 1 mol Ag3 PO4
3) As you see 3 moles of Silver Nitrate react with 1 mol of Na3 PO4, then you will need.
The you need to use the molar ratio 1:3 to calculate the number of moles of sodium phosphate
1 mol Ag NO3 * [ 1 mol Na3 PO4 / 3 mol Ag NO3] = 0.33 mol Na3 PO4
Answer: 0.33 mol sodium phosphate