Given:
AB is the diameter of a circle.
m∠CAB = 26°
To find:
The measure of m∠CBA.
Solution:
Angle formed in the diameter of a circle is always 90°.
⇒ m∠ACB = 90°
In triangle ACB,
Sum of the angles in the triangle = 180°
m∠CAB + m∠ACB + m∠CBA = 180°
26° + 90° + m∠CBA = 180°
116° + m∠CBA = 180°
Subtract 116° from both sides.
116° + m∠CBA - 116° = 180° - 116°
m∠CBA = 64°
The measure of m∠CBA is 64°.
Answer:
Step-by-step explanation:
4. 10x + 30 = 90
10x = 60
x = 6
complementary
5. 4x + 40 + 3x = 180
7x + 40 = 180
7x = 140
x = 20
supplementary
2000=1800(1.04)^t,,log(1.11)/log(1.04)=t use the calculator,,,hope it helps :-)
Answer:
5.
1. a
2.d
3.b
4.e
5.c
Step-by-step explanation:
can't do question 6 though, sorry about that
15 vg
18 vg
Just put a line in-between them to make a fraction.
