All categories

3 years ago

A balloon has a volume of 3.0 L at room temperature (27oC). At what temperature would the balloon have a volume of 4.0L?

Chemistry

1 answer:

diamong [38]3 years ago

6 0

Answer: 400K

Explanation:

Given that,

Original volume of balloon V1 = 3.0L

Original temperature of balloonT1 = 27°C

Convert the temperature in Celsius to Kelvin

(27°C + 273 = 300K)

New volume of balloon V2 = 4.0L

New temperature of balloon T2 = ?

Since volume and temperature are given while pressure is constant, apply the formula for Charle's law

V1/T1 = V2/T2

3.0L/300K = 4.0L/T2

To get the value of T2, cross multiply

3.0L x T2 = 4.0L x 300K

3.0LT2 = 1200LK

Divide both sides by 3.0L

3.0LT2/3.0L = 1200LK/3.0L

T2 = 400K

Thus, at a temperature of 400 Kelvin, the balloon would have a volume of 4.0L.

You might be interested in

Onsider the chemical system: H2(g)+I2(g)------>2HI(g)

luda_lava [24]

Answer:

The equation $\frac{[HI]^{2} }{[H_{2}[I_{2} ] }$ represent

(1) law of mass action

(2) mass action expression

(3) equilibrium constant expression

Explanation:

At a given temperature, the rate of a reaction at a particular instant is proportional to the product of the active masses of the reactants at that instant raised to powers which are numerically equal to the numbers of their respective molecules in the stoichiometric equation describe the reaction.

3 0

3 years ago

What is the mass of potassium iodide (166.00 g/mol) that yields 0.500 g of lead(ii) iodide (461.0 g/mol) precipitate? (you must

timama [110]

the mass of potassium iodide is 0.360 g

calculation

step 1: write the balanced molecular equation

Pb(NO3)2 (aq) + 2 Ki (s)→ Pbi2(s) + 2KNO3

step 2 ; calculate the moles of Pbi2

moles = mass /molar mass

= 0.500 g / 461 .0 g/mol =0.0011 moles

step 3: use the mole ratio to calculate the moles of Ki

Ki: Pbi2 is 2:1 therefore the moles of ki = 0.0011 x 2/1 = 0.0022 moles

step 4 : find the mass of Ki

mass= moles x molar mass

=0.0022 moles x 166g/mol =0.365 g which is approximate 0.360 g

8 0

3 years ago

In the presence of excess oxygen, methane gas burns in a constant-pressure system to yield carbon dioxide and water: CH4 (g) + 2

djyliett [7]

Answer:

-100.125

Explanation:

We are given

CH4 (g) + 2O2 (g) → CO2 (g) + 2H2O (l) △H = -890.0 kJ/mol

The given information is for complete reaction

we have 1.8grams of Methane

Molar mass of CH4 = 16

No of moles of Methane = 1.8/ 16

= 0.1125

So the amount of the heat will be released from the amount of the methane

Q = No of moles*( -890.0 kJ/mol)

= 0.1125*(-890)

= -100.125kJ/mole

Therefore the amount of Energy released from 1.8 grams of methane is equal to -100.125

3 0

3 years ago

A nuclear power plant is used to generate:

galben [10]

Answer:

Anuclear power plant is used to generate electricity

6 0

3 years ago

Read 2 more answers

How many glucose molecules are in 4,56 g?

shutvik [7]

Answer:

6.9768

one gram glucose molecule=1.53

4 0

4 years ago

Read 2 more answers