Which one is an accurate description of an erosion?

What is the valence electron configuration for the oxygen atom

Lana71 [14]

Oxygen has six valence (outer-shell) electrons so therefore gains two more electrons to form the O-2 ion Its electron configuration is: 1s2 2s2 2p6 or Ne

If this helped mark Brainliest!

8 0

3 years ago

What's a word equation

Yuri [45]

A word equation is a chemical reaction described using words.
A common example is the act of photosynthesis - the process plants use to make glucose (sugar) to use as 'food'.
Plants convert water and carbon dioxide into oxygen and glucose.
A word equation to express this is:
Water + Carbon Dioxide → Glucose + Oxygen
The other type of equation is a symbol equation - this uses the symbols of the elements instead of the common names:
H₂O + CO₂ → C₆H₁₂O₆ + O₂
There is also a balanced version:
6H₂O + 6CO₂ → C₆H₁₂O₆ + 6O₂
<em>If you want information on the balanced symbol equations, feel free to PM me.</em>

3 0

3 years ago

An example of a physical property of an element is the element’s ability to(1) react with an acid(2) react with oxygen(3) form a

Thepotemich [5.8K]

<span>4: Form An Aqueous Solution

This is the only answer that can be observed without testing gear and with the naked eye.... Hope I helped ^-^</span>

5 0

4 years ago

Read 2 more answers

What are the three types of protist and how are they similar and how are they different (this is science but there is no tab for

allochka39001 [22]

Answer:

They are eukaryotic, which means they have a nucleus. Most have mitochondria

3 0

3 years ago

Write a balanced nuclear equation for the formation of 28 Si 14 from beta-minus emission.

Fantom [35]

Answer:

Phosphorus-28 undergoes beta-minus decay to produce

an electron,
a Silicon-28 nuclei, and
an electron antineutrino.

$\rm ^{28}_{13} Al \to ^{28}_{14} Si + ^{\phantom{-}0}_{-1}e + \bar{\mathnormal{v}}_{\rm e}$

Explanation:

In simple words, when a nucleus undergoes beta-minus decay, a neutron is converted to a proton. An electron and an electron antineutrino will be released.

$\rm ^{1}_{0}n^{0} \to ^{1}_{1}p^{+} + ^{\phantom{-}0}_{-1}e^{-} + \bar{\mathnormal{v}}_{\rm e}$ .

One way to tell whether a neutron is converted to a proton, but not vice versa, is to check the sum charges on the two sides of this equation.

Left-hand side: 0. Neutron is neutral.
Right-hand side: 1 + (-1) = 0. Each proton carries a charge of +1. Each electron (beta-minus particle) carries a charge of -1. Antineutrinos are neutral.

The charges on the two sides of this equation is the same. Hence this nuclear equation is possible (but not necessarily correct; however, if the proton and the neutron are in the wrong place the charge won't even be the same.)

Since the mass number of a proton and a neutron are both 1, the overall mass number of the atom will stay the same.

The atomic number is the number of protons in each atom. That number determines the symbol and the chemical properties of the atom. When one neutron in an atom is converted to a proton, the atomic number of the atom will increase by 1.

The atomic number of the daughter nucleus, silicon, is 14. It takes a parent nucleus with atomic number $14 - 1 = 13$ to produce a silicon atom. Refer to a modern periodic table. Atomic number $13$ corresponds to the element aluminum.

Also, the mass number of the daughter nucleus is 28. Since the mass number would stay the same in a beta decay, the mass number of the parent nucleus would also be 28. In other words, it takes an aluminum-28 atom to undergo beta-decay to produce a silicon-28 atom.

Complete the other details (electron and electron antineutrino) to obtain the equation

$\rm ^{28}_{13} Al \to ^{28}_{14} Si + ^{\phantom{-}0}_{-1}e + \bar{\mathnormal{v}}_{\rm e}$ .

6 0

3 years ago