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3 years ago

What factors are included on a phase diagram?

Chemistry

1 answer:

Pavel [41]3 years ago

4 0

Answer:

A. Temperature and pressure

Explanation:

The factors included in a phase diagram are the temperature and pressure conditions.

A phase diagram is a combined plot of three curves all in equilibrium;

Solid- liquid, liquid -gas, and solid -gas plots

On the vertical axis, we usually have the pressure
On the horizontal axis is where the temperature is represented.
Most phase diagrams are used in chemistry and mineralogy to show areas in which different phases can exist at equilibrium.

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11. If there are 8.24 x 1022 molecules of NaCl in a salt shaker, what is the mass of the salt?

vlada-n [284]

Answer: 8.12 g NaCl

Explanation: Use Avogadro's number to find the number of m

moles of NaCl:

8.24x10²² molecules NaCl / 1 mole NaCl/ 6.022x10²³ molecules NaCl

= 0.14 mole NaCl

Next convert moles to grams NaCl using its molar mass;

0.14 mole NaCl x 58g NaCl / 1 mole NaCl

= 8.12 g NaCl

6 0

3 years ago

In a test of an automobile engine 1.00 L of octane (702 g) is burned, but only 1.84 kg of carbon dioxide is produced. What is th

Reptile [31]

Answer:

The % yield of CO2 is 85.05 %

Explanation:

Step 1: Data given

Mass of octane = 702 grams

Molar mass octane = 114.23 g/mol

Mass CO2 =1.84 kg = 1840 grams

Molar mass of CO2

Step 2: The balanced equation

2C8H18 + 25O2 → 16CO2 + 18H2O

Step 3: Calculate moles of octane

Moles octane = mass octane / molar mass octane

Moles octane = 702.0 grams / 114.23 g/mol

Moles octane = 6.145 moles

Step 4: Calculate moles of CO2

For 2 moles octane we need 25 moles O2 to produce 16 moles CO2 and 18 moles H2O

For 6.145 moles octane we'll have 8*6.145 moles =49.16 moles

Step 5: Calculate mass of CO2

Mass CO2 = moles CO2 * molar mass CO2

Mass CO2 = 49.16 moles * 44.01 g/mol

Mass CO2 = 2163.5 grams

Step 6: Calculate % yield of carbon dioxide

% yield = (actual yield / theoretical yield)*100%

% yield = (1840/2163.5)*100%

% yield = 85.05 %

The % yield of CO2 is 85.05 %

4 0

3 years ago

Make the following conversion. 120 mL = _____ cm³ 12.0 1200 120 1.20

Lina20 [59]

The correct answer would be 120.

4 0

3 years ago

Read 2 more answers

What is the mass, in grams, of

DIA [1.3K]

Answer:

The answers to your question are below

Explanation:

a) 6.85×1020 H2O2 molecules

H2O2 MW = 32 + 2 = 34 g

34g -------------------- 6.023 x 10²³ molecules

x ------------------- 6.85 x 10 ²⁰

x = (6.85 x 10 ²⁰)(34)/ 6.023 x 10²³

x = 0.038 g

3.3×1022 SO2 molecules

MW SO2 = 32 + 32 = 64g

64 g -------------------- 6.023 x 10²³ molecules

x -------------------- 3.3×1022 SO2 molecules

x = (3.3×1022 SO2)(64) / 6.023 x 10²³

x = 3.51 g

5.5×1025 O3 molecules

MW = 16 x 3 = 48g

48 g ----------------- 6.023 x 10²³ molecules

x ------------------ 5.5×1025 O3 molecules

x = (5.5×1025 )(48) / 6.023 x 10²³

x = 4383 g

9.30×1019 CH4 molecules

MW = 12 + 4 = 16 g

16 g -------------------- 6.023 x 10²³ molecules

x -------------------- 9.30×1019 CH4 molecules

x = (9.30×1019)(16) / 6.023 x 10²³

x = 0.0025 g

4 0

2 years ago

students used a balance and a graduated cylinder to collect the data shown in table 7. calculate the density of the sample. if t

Licemer1 [7]

Answer:

Percentage error = 1.88 %

Solution:

Data Given:

Mass of Sample = 20.46 g

Volume of Sample = 43.0 mL - 40.0 mL = 3.0 mL

Formula Used:

Density = Mass / Volume

Putting values,

Density = 20.46 g / 3.0 mL

Density = 6.82 g.mL⁻¹

Percentage Error:

Experimental Value = 6.82 g.mL⁻¹

Accepted Value = 6.95 g.mL⁻¹

= 6.82 g.mL⁻¹ / 6.95 g.mL⁻¹ × 100 = 98.12 %

Percentage Error = 100 % - 98.12 %

Percentage error = 1.88 %

3 0

2 years ago