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3 years ago

Why is burning wood a chemical change?

1 answer:

3 0

There are 4 things that are evidence of a chemical change.
1)Change in color
2)Change in shape (gas being let out)
3)Change in temperature
4)Change in smell

Burning wood is a chemical change because it has a change in color, and shape.

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34 points please help!!!!!!!!

Shtirlitz [24]

Answer:

(i think) it is A difference in 1 unit is a 10X difference in concentration For example; a liquid with pH of 3 is 10X more acidic than a liquid with a pH of 4. Therefore, a liquid with a pH of 3 is stronger.

Explanation:

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3 years ago

Can you guys help me.

Alisiya [41]

<span>1. Formula 2. Reactants 3. Atoms & molecules 4. Destroyed or created 5. Balanced 6. Mass number 7. 2Al(s) + 3CuCl2(aq) = 2AlCl3(aq) + 3Cu(s)</span>

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3 years ago

At a particular temperature, K = 4.1 ✕ 10−6 for the following reaction. 2 CO2(g) 2 CO(g) + O2(g) If 2.3 moles of CO2 is initiall

mestny [16]

Answer:

concentration of $[O_2]$ = 0.0124 = 12.4 ×10⁻³ M

concentration of $[CO]$ = 0.0248 = 2.48 ×10⁻² M

concentration of $[CO_2]$ = 0.4442 M

Explanation:

Equation for the reaction:

$2CO_2_{(g)$ ⇄ $2CO_{(g)$ + $O_2_{(g)$

Concentration of $CO_2_{(g)$ = $\frac{2.3}{4.9}$ = 0.469

For our ICE Table; we have:

$2CO_2_{(g)$ ⇄ $2CO_{(g)$ + $O_2_{(g)$

Initial 0.469 0 0

Change - 2x +2x +x

Equilibrium (0.469-2x) 2x x

K = $\frac{[CO]^2[O]}{[CO_2]^2}$

K = $\frac{[2x]^2[x]}{[0.469-2x]^2}$

$4.1*10^{-6}=\frac{2x^3}{(0.469-2x)^2}$

Since the value pf K is very small, only little small of reactant goes into product; so (0.469-2x)² = (0.469)²

$4.1*10^{-6} = \frac{2x^3}{(0.938)}$

$2x^3 =3.8458*10^{-6$

$x^3 =\frac{3.8458*10^{-6}}{2}$

$x^3=1.9229*10^{-6$

$x=\sqrt[3]{1.9929*10^{-6}}$

x = 0.0124

∴ at equilibrium; concentration of $[O_2]$ = 0.0124 = 12.4 ×10⁻³ M

concentration of $[CO]$ = 2x = 2 ( 0.0124)

= 0.0248

= 2.48 ×10⁻² M

concentration of $[CO_2]$ = 0.469-2x

= 0.469-2(0.0124)

= 0.469 - 0.0248

= 0.4442 M

3 0

3 years ago

Draw a line graph showing the population of beetles and healthy trees in the forest for five years. Round the numbers to the nea

Sergio [31]

how do i draw a line ghraph on a computer

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3 years ago

Read 2 more answers

Consider the following reaction at equilibrium. What effect will adding some C have on the system?CO2(g) + C(graphite) ↔ 2 CO(g)

sashaice [31]

Answer:

No effect will be observed since C is not included in the equilibrium expression.

Explanation:

Let's consider the following reaction.

CO₂(g) + C(graphite) ↔ 2 CO(g)

The equilibrium constant (Kc) is the product of the concentration of the products raised to their stoichiometric coefficients divided by the product of the concentration of the reactants raised to their stoichiometric coefficients.

Kc only includes gases and aqueous species (not liquids or solids).

$Kc=\frac{[CO]^{2}}{[CO_{2}]}$

As we can see, C is a solid and is not included in the equilibrium expression, so adding some C would have no effect on it.

4 0

3 years ago