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Xelga [282]
3 years ago
15

What is the end behavior of the function h? H(x)=-4x+4

Mathematics
1 answer:
lara31 [8.8K]3 years ago
5 0

Answer:

Below

Step-by-step explanation:

The end behavior of a function is how it grows when it reaches both plus and - infinity.

To do that we will calculate:

● lim h(x) x=> +infinity = lim-4x+4 x=> +inf = lim -4x x=> +inf

-4 is negative so the limit will be -infinity

● lim (-4x+4) x=> -inf = lim (-4x) x=> -inf

-4 is negative, x is negative then -4x is positive. So the limit will be + inf

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<img src="https://tex.z-dn.net/?f=p%5E%7B3%7D%20at%20%5C%5C%5C%5C%20p%20%3D%202" id="TexFormula1" title="p^{3} at \\\\ p = 2" al
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Reason:

Replace p with 2 and evaluate.

p^3 = 2^3 = 2*2*2 = 8

Think of a cube that is 2 units along each side. It's volume is 2*2*2 = 8 cubic units. Repeated multiplication can be shortened to using exponents.

Another example: 7^4 = 7*7*7*7

6 0
2 years ago
Which formula can be used to find the nth term of a geometric sequence where the fifth term is 1/6 and the common ratio is 1/4?
OlgaM077 [116]

Answer:

a_n = 16(\frac{1}{4})^{n - 1}

Step-by-step explanation:

Given:

Fifth term of a geometric sequence = \frac{1}{16}

Common ratio (r) = ¼

Required:

Formula for the nth term of the geometric sequence

Solution:

Step 1: find the first term of the sequence

Formula for nth term of a geometric sequence = ar^{n - 1}, where:

a = first term

r = common ratio = ¼

Thus, we are given the 5th term to be ¹/16, so n here = 5.

Input all these values into the formula to find a, the first term.

\frac{1}{16} = a*\frac{1}{4}^{5 - 1}

\frac{1}{16} = a*\frac{1}{4}^{4}

\frac{1}{16} = a*\frac{1}{256}

\frac{1}{16} = \frac{a}{256}

Cross multiply

1*256 = a*16

Divide both sides by 16

\frac{256}{16} = \frac{16a}{16}

16 = a

a = 16

Step 2: input the value of a and r to find the nth term formula of the sequence

nth term = ar^{n - 1}

nth term = 16*\frac{1}{4}^{n - 1}

a_n = 16(\frac{1}{4})^{n - 1}

3 0
3 years ago
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