Answer:
a) = 3.94 m
b) = 3.15 m
Explanation:
Given
Mass of the block, m = 242 g
Force constant, k = 1.62 kN/m
Compression of the spring, x = 10 cm
Angle of inclination = 60°
a) if we equate the energy at the bottom of the ramp to the energy at a distance d up the ramp, we have
1/2kx² = mgh where, h = dsinΦ
1/2kx² = mgdsinΦ
1/2 * 1.62*10^3 * 0.1² = 0.242 * 9.8 * dsin 60
1/2 * 16.2 = 2.3716 * d sin 60
d sin 60 = 8.1 / 2.3716
0.866 d = 3.415
d = 3.415 / 0.866
d = 3.94 m
b) net force on the block = mgd sin 60 + µ mgd cos 60
8.1 = d[mg sin 60 + µ mg cos 60]
8.1 = d [0.242 * 9.8 * 0.866 + 0.44 * 0.242 * 9.8 * 0.5]
8.1 = d (2.05 + 0.52)
8.1 = 2.57 d
d = 8.1 / 2.57
d = 3.15 m
The force exerted on the tires of a car that directly accelerate it along a road is exerted by the road friction.
<h3>What is force?</h3>
Force is defined as the product of mass and acceleration of an object.
Friction is defined as the force that resists the movement of an object over another.
Therefore, the force exerted on the tires of a car that directly accelerate it along a road is exerted by the road friction.
Learn more about force here:
brainly.com/question/12970081
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The wavelength of the golf ball is <u>2.328×10⁻³⁴m.</u>
All moving particles with mass have a matter wave associated with it. These matter waves are called deBroglie waves.
The deBroglie wavelength λ of a particle is given by,
Here, h is the Planck's constant, m is the mass of the ball and v is its velocity.
Calculate the deBroglie wavelength of the moving golf ball by substituting 6.626×10⁻³⁴J s for h, 45.9×10⁻³kg for m and 62.0 m/s for v.
The wavelength of the golf ball is <u>2.328×10⁻³⁴m.</u>
