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2 years ago

Find the ratio of the Coulomb electric force Fe to the gravitational force Fo between two

Physics

1 answer:

Leya [2.2K]2 years ago

6 0

Answer:

thus the coulomb force is F – 8.19x10-8N. this is also an attractive force, although it is traditionally shown as positive since gravitational force is always attractive. the ratio of the magnitude of the electrostatic force to gravitational force in this case is,thus,FFG – 2.27x1039 F F G – 2.27x 10 39.

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A transverse wave causes its medium to move in what direction?

Mariulka [41]

Answer:

Explanation:

A transverse wave is a wave in which particles of the medium move in a direction perpendicular to the direction that the wave moves. Suppose that a slinky is stretched out in a horizontal direction across the classroom and that a pulse is introduced into the slinky on the left end by vibrating the first coil up and down.

8 0

3 years ago

Read 2 more answers

A wave has a wavelength of 6 mm and a frequency of 9 hertz. What is its speed? what is the answer and units?

Lisa [10]

Answer:The speed is 54 mm/s, the units are mm/s.

Explanation:

1) Data:

a) λ = 6mm
b) f = 9 Hz = 9 s⁻¹
c) v = ?

2) Formula:

wave equation: v = f × λ

3) Solution:

v = 9 s⁻¹ × 6mm

v = 54 mm/s

The speed is 54 mm/s, the units are mm/s.

5 0

3 years ago

What is the amplitude of an AC voltage waveform, in units of Volts, if the RMS value is 369 V?

Blizzard [7]

Answer:

521.8 V

Explanation:

The RMS value of the voltage of an AC signal is given by

$V_{rms}=\frac{V_0}{\sqrt{2}}$

where

$V_0$ is the peak voltage, which corresponds to the amplitude of the AC waveform

In this problem, we know the RMS voltage

$V_{rms}=369 V$

Therefore, we can re-arrange the previous equation to find the peak voltage (the amplitude of the waveform):

$V_0 = \sqrt{2}V_{rms}=\sqrt{2}(369 V)=521.8 V$

4 0

3 years ago

At what net rate does heat radiate from a 300-m^2 black roof on a night when the roof's temperature is 33.0°C and the surroundin

Fynjy0 [20]

Answer:

24445.85 J/s

Explanation:

Area, A = 300 m^2

T = 33° C = 33 + 273 = 306 k

To = 18° C = 18 + 273 = 291 k

emissivity, e = 0.9

Use the Stefan's Boltzman law

$E = \sigma \times e \times A\times\left ( T^4 -T_{0}^{4}\right )$

Where, e be the energy radiated per unit time, σ be the Stefan's constant, e be the emissivity, T be the temperature of the body and To be the absolute temperature of surroundings.

The value of Stefan's constant, σ = 5.67 x 10^-8 W/m^2k^4

By substituting the values

$E = 5.64 \times 10^{-8}\times 0.9 \times 300 \times (306^{4}-291^{4})$

E = 24445.85 J/s

7 0

3 years ago

Can someone please answer how to convert mass into weight?

Rasek [7]

Answer:

To find the weight of something, simply multiply its mass by the value of the local gravitational field, and you get a result in newtons (N). For example, if your mass is 50 kg (about 110 pounds), then your weight is (50) (9.8). The point that must be overwhelmingly emphasized is that weight is a force.

Explanation:

4 0

3 years ago