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Marta_Voda [28]
3 years ago
15

Compare an electrically neutral atom of oxygen and an isotope of oxygen.

Chemistry
1 answer:
Leya [2.2K]3 years ago
6 0
<span>An atom containing an equal number of protons and electrons is electrically neutral, otherwise it has a positive charge if there are fewer electrons (electron deficiency) or negative charge if there are more electrons (electron excess).</span>
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The volume occupied by 1.5 mol of gas at 45°c and 2.5 atm pressure is __________ l.
Kitty [74]
We are going to apply the equation of state for ideal gasses: P*V = n*R*T  where P is pressure, V is volum, n is mols of gas, T is temperature and R is a constant value of 0.082 (atm*l)/(mol*K)  
We know the temperature is 45 ÂşC so in Kelvins will be = 45 + 273.16 = 318.16 K  
Then in the equation:  
V = n*R*T/P = 1.5 * 0.082 * 318.16 / 2.5 = 15.65 l  
So volum of gas is: 15.65 liters
8 0
4 years ago
Dmitri Mendeleev's Periodic Law states that chemical and physical properties repeat themselves in groups of _____. A. 4 B. 8 C.
krok68 [10]
<span>Dmitri Mendeleev's Periodic Law states that chemical and physical properties repeat themselves in groups of 8.</span>
6 0
4 years ago
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According to Newton’s Third Law, if someone jumps off a skateboard, the skateboard will roll backwards because -
Andrej [43]

Answer:

for the force that sent the person forward, there is an equal force pushing back on the skateboard

5 0
4 years ago
Describe the changes in energy that occur when a marshmallow is burned over a fire?
boyakko [2]

Answer:

When marshmallows are toasted, a chemical change occurs. The sugar molecules in the marshmallow are being changed into carbon (1). Sugar can be changed into water molecules. ... The flame on stage - oxygen diffuses to the surface of the marshmallow from the surrounding air.

6 0
4 years ago
a piece of newly synthesized material of mass 25.0 g at 80.0C is placed in a calorimeter containing 100.0 g of water at 20.0C. I
serg [7]

Answer:

The correct answer is 1.194 J/g.ºC

Explanation:

The heat released by the material is absorbed by the water. We put a minus sign (-) for a released heat and a plus sign (+) for an absorbed heat.

We know the mass of the material (mass mat= 25.0 g) and the mass of water (mass H20= 100.0 g) and the specific heat capacity of water is known (Shw=4.18 J/g.ºC), so we can equal the heat released by the material and the heat absorbed by water y calculate the specific heat capacity of the material (Shm) as follows:

heat released by material = heat absorbed by water

-(mass material x Shm x ΔT)= mass water x Shw x ΔT

-(25.0 g x Shm x (24ºC - 80ºC)= 100.0 g x 4.18 J/g.ºC  x (24ºC-20ºC)

25.0 g x Shm x (56ºC) =  100.0 g x 4.18 J/g.ºC x 4ºC

⇒Shm= (100.0 g x 4.18 J/g.ºC x 4ºC)/(25.0 g x 56ºC)

 Shm= 1.194 J/g.ºC

5 0
3 years ago
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