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Kitty [74]
3 years ago
7

A car moving at 12 m/s applies its brakes and comes to a stop in 2 s. What was its acceleration?​

Chemistry
1 answer:
vredina [299]3 years ago
8 0

Answer:

<h2>6 m/s²</h2>

Explanation:

The acceleration of an object given it's velocity and time taken can be found by using the formula

a =  \frac{v}{t}  \\

where

a is the acceleration

v is the velocity

t is the time

From the question we have

a =  \frac{12}{2}  \\

We have the final answer as

<h3>6 m/s²</h3>

Hope this helps you

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A sealed flask contains Ne, Ar, and Kr gas. If the total pressure in the flask is 3.782 atm, the partial pressure of Ne is 0.435
spin [16.1K]

Answer:

P_{Ar}=1.734atm = partial pressure of Ar

Explanation:

Acccoding to dalton's law of partial pressure total pressure of system is equal to alzebraic sum of all partial pressure.

P_{total} =P_{Ne}+P_{Ar} +P_{Kr}

P_{total}=3.782atm

P_{Ne}=0.435 atm

P_{Kr}=1.613atm

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Consider the following equilibrium systems: A⇌2B ΔH o =20.0 kJ/mol Reaction 1 A+B⇌C ΔH o =−5.4 kJ/mol Reaction 2 A⇌B ΔH o =0.0 k
galina1969 [7]

Answer:

Reaction 1: Kc increases

Reaction 2: Kc decreases

Reaction 3: The is no change

Explanation:

Let us consider the following reactions:

Reaction 1: A ⇌ 2B ΔH° = 20.0 kJ/mol

Reaction 2: A + B ⇌ C ΔH° = −5.4 kJ/mol

Reaction 3: 2A⇌ B ΔH° = 0.0 kJ/mol

To predict what will happen when the temperature is raised we need to take into account Le Chatelier Principle: when a system at equilibrium suffers a perturbation, it will shift its equilibrium to counteract such perturbation. This means that <em>if the temperature is raised (perturbation), the system will react to lower the temperature.</em>

Reaction 1 is endothermic (ΔH° > 0). If the temperature is raised the system will favor the forward reaction to absorb heat and lower the temperature, thus increasing the value of Kc.

Reaction 2 is exothermic (ΔH° < 0). If the temperature is raised the system will favor the reverse reaction to absorb heat and lower the temperature, thus decreasing the value of Kc.

Reaction 3 is not endothermic nor exothermic (ΔH° = 0) so an increase in the temperature will have no effect on the equilibrium.

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