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dem82 [27]
3 years ago
11

What color change is exhibited by phenolphthalein during a titration of aqueous acetic acid with aqueous sodium hydroxide ? a. c

olorless to pink b. pink to colorless c. no color change d. yellow to blue e blue to yellow
Chemistry
1 answer:
Agata [3.3K]3 years ago
4 0
Phenolphthalein during a titration
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Calculate the number of atoms in 2.8 moles of silicon atoms
IceJOKER [234]

Answer:

<h2>1.686 × 10²⁴ atoms</h2>

Explanation:

The number of silicon atoms can be found by using the formula

<h3>N = n × L</h3>

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 2.8 × 6.02 × 10²³

We have the final answer as

<h3>1.686 × 10²⁴ silicon atoms</h3>

Hope this helps you

5 0
4 years ago
How many ml of 12.0 M H2S04 are needed to make 500.0 ml of a 1.00 M solution? What happens to the freezing point and the boiling
lora16 [44]

Answer:

41.66 mL of 12.0 M sulfuric acid are needed.

Explanation:

Concentration of sulfuric acid solution taken =M_1=12.0M

Volume of the 12.0 M Solution = V_1

Concentration of required solution = M_2=1.00M

Volume of required 1.00 M solution = V_2=500.0 mL

M_1V_1=M_2V_2 (Dilution)

V_1=\frac{1.00 M\times 500.0 mL}{12.0 M}=41.66 mL

41.66 mL of 12.0 M sulfuric acid are needed.

The freezing point and the boiling point of a solvent when a non-volatile solute is dissolved in it decrease and increase respectively.

3 0
4 years ago
What phrase best describes hematite​
alekssr [168]

Answer:

mark as brainliest pls

Explanation:

Hematite can be described as a rock which contains a lot of iron. Hematite is an ore of iron from which substantial amount of iron can be won at profit depending on prevailing economic conditions in a place

8 0
3 years ago
After 42 days, a 2.0 g sample of phosphorous-32 contains only 0.25 g of the isotope. What is the half-life of phosphorus-32?
tester [92]

Answer:

Half life of phosphorous-32 = 14 days

Explanation:

Given data:

Total mass of phosphorous-32 = 2.0 g

After 42 days mass left = 0.25 g

Half life of phosphorous-32 = ?

Solution:

First of all we will calculate the number of half lives passed.

At time zero = 2.0 g

At first half life = 2.0 g/2 = 1.0 g

At 2nd half life = 1.0 g/2 = 0.5 g

At 3rd half life = 0.5 g/2 = 0.25 g

Half life:

Half life = T elapsed / half lives

Half life = 42 days/ 3

Half life = 14 days

4 0
3 years ago
Please compare between physical and chemical properties of matter<br>​
stealth61 [152]

Answer:

A physical property is a characteristic of a substance that can be observed or measured without changing the identity of the substance. Physical properties include color, density, hardness, and melting and boiling points. A chemical property describes the ability of a substance to undergo a specific chemical change

Explanation:

I got this from chem.libretexts.org in case you wanted to know

5 0
3 years ago
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