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dem82 [27]
3 years ago
11

What color change is exhibited by phenolphthalein during a titration of aqueous acetic acid with aqueous sodium hydroxide ? a. c

olorless to pink b. pink to colorless c. no color change d. yellow to blue e blue to yellow
Chemistry
1 answer:
Agata [3.3K]3 years ago
4 0
Phenolphthalein during a titration
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What did the early atomic theory
Virty [35]

Answer:B

Explanation:

The early theory says that atom Is the smallest indivisible particle. Which was later proven to contain electron neutron and proton

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4 years ago
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How does the entropy of a system change when equal volumes of ethanol and water are mixed to form a solution? these are the answ
shutvik [7]
When equal volumes of ethanol and water are mixed to form a solution, the entropy of the resulting solution increases. This is because ethanol and water are both polar substances, making them miscible. The solubility of both substances is high because they have similar attractions due to the presence of hydrogen bonding. This means that molecules of water and ethanol freely move with each other, therefore increasing the dispersal, randomness, and disorder (entropy) of the system.
5 0
3 years ago
Type the correct answer in each box.
krok68 [10]

Answer:

2KI → 2K + I₂

Explanation:

(not my definition, but form a trustworthy source)

The definition of a decomposition reaction is:

a chemical reaction in which one reactant breaks down into two or more products.

In this case, potassium iodide will decompose into potassium and iodine.

2KI → 2K + 2I

2 Potassium and 2 Iodine on both sides, so equation is balanced.

Or, it can be written as 2KI → 2K + I₂

8 0
2 years ago
2. A solution is 0.01 M in Ba2+ and 0.01 M in Ca2+. Sodium sulfate is added to selectively precipitate one of the cations, while
lozanna [386]

Answer:

Explanation:

The solution contain  0.01 M concentration of Ba²⁺

0.01M concentration of Ca²⁺

Ksp ( solubility constant) for BaSO₄ = 1.07 × 10⁻¹⁰

Ksp for CaSO₄ = 7.10 × 10⁻⁵

(BaSO₄) = (Ba²⁺) (SO₄²⁻)

1.07 × 10⁻¹⁰ = 0.01 M (SO₄²⁻)

1.07 × 10⁻¹⁰ / 0.01 = ( SO₄²⁻)

1.07 × 10⁻⁸ M = ( SO₄²⁻)

so the minimum of concentration of concentration sulfate needed is 1.07 × 10⁻⁸ M

For CaSO₄

CaSO₄ = ( Ca²⁺) (  SO₄²⁻)

7.10 × 10⁻⁵  = 0.01 (SO₄²⁻)

(SO₄²⁻) = 7.10 × 10⁻⁵   / 0.01 = 7.10 × 10⁻³ M

so BaSO₄ will precipitate first since its cation (0.01 M Ba²⁺) required a less concentration of SO₄²⁻ (1.07 × 10⁻⁸ M ) compared to CaSO₄

b) The minimum concentration of SO₄²⁻ that will trigger the precipitation of the cation ( 0.01 M Ba²⁺) that precipitates first is 1.07 × 10⁻⁸ M

7 0
4 years ago
How many grams of Copper are in 500grams of Cu2CO3?
Novay_Z [31]

Answer:

≈170.22 [gr].

Explanation:

1) M(Cu₂CO₃)=2*64+12+3*16=188 [gr/mol];

2) the part of copper in Cu₂CO₃ is:

\frac{64}{188} =\frac{16}{47};

3) 16/47% of 500 [gr] is:

500*\frac{16}{47}=170.22[gr].

7 0
2 years ago
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