Answer: 30 °C
Explanation:
86 degrees Fahrenheit = 30 degrees Celsius
86°f to degrees Celsius is 30°c.
Answer:
The type of reaction that is occuring is 164.8 kJ.
Answer:
filter the hot mixture.
Explanation:
Solid is stayed undissolved since the arrangement is gotten super saturated. On the off chance that solid molecule is available recrysallization won't happen in this way we need expel the solid molecule by filtarion in hot condition itself . Subsequently, arrangement become totally homogenous and recrysallization item will shaped by moderate cooling
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The correct option would be 'electrons'
This is because electrons have a relative mass of zero.
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Answer: ![[OH^{-}]= 0.01M or 1.0\times 10^{-2}M](https://tex.z-dn.net/?f=%5BOH%5E%7B-%7D%5D%3D%200.01M%20or%201.0%5Ctimes%2010%5E%7B-2%7DM)
![[H^{+}]= 1.0\times 10^{-12}M](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%3D%201.0%5Ctimes%2010%5E%7B-12%7DM)
pH = 12
pOH = 2
Explanation: Calcium hydroxide (
) is a strong base that dissociates completely.
Dissociation equation of Calcium hydroxide is :

1. Concentration of [OH-]
1 mol
produces 2 mol OH- ions.
The given solution is 0.005M
, then concentration of OH- would be twice the concentration of 
= 0.01M or 
2.Concentration of [H+]
Concentration of [H+] can be calculated by the formula: ![[H^{+}] = \frac{Kw}{[OH^{-}]}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%20%3D%20%5Cfrac%7BKw%7D%7B%5BOH%5E%7B-%7D%5D%7D)
kw = ionic product of water and its values is 
[OH-] = 0.01 M or 
![[H^{+}] = \frac{(1\times 10^{-14})}{[OH^{-}]}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%20%3D%20%5Cfrac%7B%281%5Ctimes%2010%5E%7B-14%7D%29%7D%7B%5BOH%5E%7B-%7D%5D%7D)
![[H^{+}] = \frac{(1\times 10^{-14})}{[0.01]}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%20%3D%20%5Cfrac%7B%281%5Ctimes%2010%5E%7B-14%7D%29%7D%7B%5B0.01%5D%7D)
![[H^{+}] = 1.0\times 10^{-12}M](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%20%3D%201.0%5Ctimes%2010%5E%7B-12%7DM%20)
3. pH value
pH is calculated by the formula : ![pH = -log[H^{+}]](https://tex.z-dn.net/?f=pH%20%3D%20-log%5BH%5E%7B%2B%7D%5D)
![pH = -log[1.0\times 10^{-12}]](https://tex.z-dn.net/?f=pH%20%3D%20-log%5B1.0%5Ctimes%2010%5E%7B-12%7D%5D)
pH = 12
4. pOH value
pOH is calculated by the formula : pOH = 14 - pH
pOH = 14 - 12
pOH = 2
pOH can also be calculated by using a different formula which is :


pOH = 2.