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ale4655 [162]
3 years ago
9

What occurs at stage A?

Chemistry
2 answers:
Semenov [28]3 years ago
6 0

Answer:

water evaporates from surfaces

Explanation:

I got it right

Alex_Xolod [135]3 years ago
4 0

Answer:

water evaporate from surfaces

Explanation:

after it clumps to air to make clouds ,cools turn to liquid and rains or precipitate and becomes runoff

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2. What temperature is equivalent to 86°F?
katrin [286]

Answer: 30 °C

Explanation:

86 degrees Fahrenheit = 30 degrees Celsius

86°f to degrees Celsius is 30°c.

6 0
3 years ago
CH,(g) + 20,(g) - CO2(g) + 2H20() + S90.4 kJ<br> What is the type of reaction that is occurring?
7nadin3 [17]

Answer:

The type of reaction that is occuring is 164.8 kJ.

3 0
3 years ago
what is the best course of action if solid material remains in the flask after the heating step of recrystallization
lys-0071 [83]

Answer:

filter the hot mixture.

Explanation:

Solid is stayed undissolved since the arrangement is gotten super saturated. On the off chance that solid molecule is available recrysallization won't happen in this way we need expel the solid molecule by filtarion in hot condition itself . Subsequently, arrangement become totally homogenous and recrysallization item will shaped by moderate cooling

7 0
4 years ago
An element's atomic mass does not include the mass of its _____.
Oksi-84 [34.3K]

。☆✼★ ━━━━━━━━━━━━━━  ☾

The correct option would be 'electrons'

This is because electrons have a relative mass of zero.

Have A Nice Day ❤

Stay Brainly! ヅ

- Ally ✧

。☆✼★ ━━━━━━━━━━━━━━  ☾

3 0
3 years ago
What is the h oh ph and poh of a 0.005m solution of calcium hydroxide?
fiasKO [112]

Answer: [OH^{-}]= 0.01M or 1.0\times 10^{-2}M

[H^{+}]= 1.0\times 10^{-12}M

pH = 12

pOH = 2

Explanation: Calcium hydroxide (Ca(OH)_{2}) is a strong base that dissociates completely.

Dissociation equation of Calcium hydroxide is :

Ca(OH)_{2} \rightarrow Ca^{+2} + 2OH^{-}

1. Concentration of [OH-]

1 mol Ca(OH)_{2} produces 2 mol OH- ions.

The given solution is 0.005M Ca(OH)_{2} , then  concentration of OH- would be twice the concentration of Ca(OH)_{2}

[OH^{-}] = 0.005\times 2 = 0.01M or 1.0\times 10^{-2}M

2.Concentration of [H+]

Concentration of [H+] can be calculated by the formula: [H^{+}] = \frac{Kw}{[OH^{-}]}

kw = ionic product of water and its values is (1\times 10^{-14})

[OH-] = 0.01 M or 1.0\times 10^{-2}M

[H^{+}] = \frac{(1\times 10^{-14})}{[OH^{-}]}

[H^{+}] = \frac{(1\times 10^{-14})}{[0.01]}

[H^{+}] = 1.0\times 10^{-12}M

3. pH value

pH is calculated by the formula : pH = -log[H^{+}]

pH = -log[1.0\times 10^{-12}]

pH = 12

4. pOH value

pOH is calculated by the formula : pOH = 14 - pH

pOH = 14 - 12

pOH = 2

pOH can also be calculated by using a different formula which is :

pOH = -log(OH^{-})

pOH = -log(0.01)

pOH = 2.


3 0
3 years ago
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