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Fittoniya [83]
2 years ago
15

The heat of vaporization of 1-pentanol is 55.5 kj/mol, and its entropy of vaporization is 148 j/k.mol. what is the approximate b

oiling point of 1-pentanol
Chemistry
1 answer:
KonstantinChe [14]2 years ago
7 0
As you can see, the unit of heat of vaporization is in kJ/mol, while the unit for entropy of vaporization is in J/mol·K. Since it is vaporization, this occurs at the boiling point. Thus, the formula would be:

Boiling Point = ΔHvap/ΔSvap

Make sure the units are consistent.

Boiling point = 55.5 kJ/mol * 1000 J/kJ / 148 J/mol·K = <em>375 K or 102°C</em>
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How many protons, electrons, and neutrons does the following isotope contain?<br> 27 A13+
Lapatulllka [165]

Hey there!

27 tells us the sum of protons and neutrons is 27.

Al tells us we have 13 protons.

3+ tells us that there are 3 less electrons than protons.

13 + n = 27

neutrons = 14

13 - 3 = 10 electrons

27Al3+ has 13 protons, 14 neutrons, and 10 electrons.

Hope this helps!

7 0
3 years ago
a bowl of cereal is at a temperature of 62 fahrenheit then the bowl of cereal thermal energy decreases as soon as mass or not ch
rewona [7]
<h3>Answer:</h3>

  53 fahrenheit

<h3>Explanation:</h3>

Temperature is a measure of thermal energy. It goes down when thermal energy decreases. Of your choices, the temperature lower than 62 °F is 53 °F.

8 0
3 years ago
The valences of metal x,y and z are 1,2 and 3 respectively. What are the formulae of their;a) hydroxides, b) sulphates, c) hydro
Rina8888 [55]

Answer:

See answer below

Explanation:

AS we know that the valence for those metals X, Y, and Z are 1, 2 and 3, we can determine the formula of each compound.

1. Hydroxides.

An hydroxide is formed when an oxyde of a metal reacts with water. When this happens, the general molecular formula is:

Meₐ(OH)ₙ

Where:

a: valence or charge of the hydroxide (Which is -1)

n: valence of the metal.

Following this, the formula for X, Y and Z would be:

XOH

Y(OH)₂

Z(OH)₃

2. Sulphates

Sulphates follow a similar rule of hydroxide in the general molecular formula, but instead of having a charge of -1, it has a charge of -2 so:

Mₐ(SO₄)ₙ

So, following the rule:

X₂SO₄

Y₂(SO₄)₂ ------> YSO₄

Z₂(SO₄)₃

3. Hydrogens

Following the same rule as the previous, hydrogens works with a charge of -1, so:

MₐHₙ

Then:

XH

YH₂

ZH₃

4. Carbonates.

This follows the same rule as sulphates, with the same charge so:

Mₐ(CO₃)ₙ

Then:

X₂CO₃

YCO₃

Z₂(CO₃)₃

5. Nitrates

Follow the same rule as the hydroxides, with the same charge of -1.

Mₐ(NO₃)ₙ

Then:

XNO₃

Y(NO₃)₂

Z(NO₃)₂

6. Phosphates

In the case of phosphates, these have a charge of -3 so:

Mₐ(PO₄)ₙ

Then:

X₃PO₄

Y₃(PO₄)₂

Z₃(PO₄)₃ ----> ZPO₄

Hope this helps

6 0
2 years ago
Which of the following is/are true regarding initial and maximal velocity of enzyme-mediated reactions?
kenny6666 [7]

Answer:

a. True

b. True

c. False

d. True

Explanation:

a). A a very low substrate concentration , $S. Thus according to the Machaelis-Menten equation becomes

$V_0 = \frac{V_{max} \times [S]}{Km}$

Here since the $V_0$ varies directly to the substrate concentration [S], the initial velocity is lower than the maximal velocity. Thus option  (a) is true.

b). The Michaelis -Menten kinetics equation states that :

   $V_0 = \frac{V_{max} \times [S]}{Km+[S]}$

  Here the initial velocity changes directly with the substrate concentration as $V_0$ is directly proportional to [S]. But $V_{max}$ is same for any particular concentration of the enzymes. Thus, option (b) is true.

c). As the substrate concentration increases, the initial velocity also increases. Thus option (c) is false.

d). Option (d) explains the procedures to estimate the initial velocity which is correct. Thus, option (d) is true.

7 0
3 years ago
What factors affect freezing-point depression of a solution? (select all that apply)
ANTONII [103]

Answer:

A and F i think

Explanation:

Freezing point depression is a colligative property observed in solutions that results from the introduction of solute molecules to a solvent. The freezing points of solutions are all lower than that of the pure solvent and is directly proportional to the molality of the solute

8 0
3 years ago
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