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3 years ago

The oxidizing agent in 2H2S + 3O2 → 2SO2 + 2H2O is

Chemistry

1 answer:

Dovator [93]3 years ago

8 0

Hello, Ginamuhs2!

The oxidizing agent in 2H2S + 3O2 → 2SO2 + 2H2O is the oxygen.

I hope this helps;)

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Pls tell me how to solve this!

Anna35 [415]

Answer:

12 seconds

Explanation:

Time taken by 50cm³ of oxygen to diffuse from pinhole

= 1 minute = 60 seconds

⠀

$\textsf{ Rate of oxygen} \sf (O_2) = \frac{50}{60}$

⠀

Let time taken by 50cm³ of hydrogen to diffuse from pinhole = t seconds

⠀

$\textsf {Rate of hydrogen } \sf(H_2) = \frac{50}{t}$

⠀

According to the formula

$\sf \frac{Rate \: of \: hydrogen(H_2)}{Rate \: of \: oxygen(O_2) } = \sqrt{ \frac{Molar \: mass \: of \: O_2}{Molar \: mass \: of \: H_2} }$

⠀

$\large \sf \frac{50}{t} \div \frac{50}{60} = \sqrt{ \frac{\cancel{32}\small 16}{\cancel2} } \\ \\ \sf \large \frac{ \cancel{50}}{t} \times \frac{60}{ \cancel{50}} = \sqrt{16} \\ \\ \sf \large \frac{60}{t} = 4 \\ \\ \sf \large \frac{ \cancel{60} \: \small12}{ \cancel4} = t \\ \\ \large \underline{ \boxed{ \tt t = 12 \: seconds}}$

⠀

<h3>Henceforth, the time taken by 50cm³ of hydrogen to diffuse is 12 seconds. </h3>

⠀

<h2>Thank you!</h2>

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