Ask question

Ask question

All categories

s344n2d4d5 [400]

3 years ago

10

Describe how to calibrate a candy thermometer

1 answer:

Mekhanik [1.2K]3 years ago

7 0

Put the thermometer into boiling water and leave it for five minutes in order to get an accurate reading. remove the thermometer and while looking at eye level see where the line of the fluid sits. if it not exactly the 100 C or 212 F marker then you need to note the difference and compensate for this amount each time you use the thermometer. If you get radically different results often, you need a knew thermometer.

You might be interested in

Steve want to catch up to Cami, a girl he likes. If he is jogging at 8 m/s and she is walking at 1 m/s. How long will it take hi

Aleks04 [339]

Answer:

<u><em>1) if they are moving away from each other it will take 1.43 secs</em></u>

<u><em>2) if they are moving towards each other then it will take 1.11 secs</em></u>

Explanation:

Distance between them is 10 m

Speed ( if they are moving towards each other)= distance/time

time = 10/8+1

time = distance / speed= 10/9= 1.11 secs

if they are moving away from each other than it will take

time = 10/8-1= 10/7= 1.43 secs

5 0

3 years ago

A 410-kg piano is being unloaded from a truck by rolling it down a ramp inclined at 25°. There is negligible friction and the ra

SpyIntel [72]

Answer:BOONK GANG

Explanation:

AHAHAHA I USE CALC LIKE IN CLASS AHAHA

5 0

4 years ago

The courtroom role that possesses the most discretion is?

KonstantinChe [14]

The role of the Prosecutor's

5 0

4 years ago

The standard unit of radiation related to biologic hazard is the:

marin [14]

Im positive that the answer is b

4 0

4 years ago

Read 2 more answers

A single-turn circular loop of wire of radius 5.0 cm lies in a plane perpendicular to a spatially uniform magnetic field. During

Artemon [7]

Answer:

Induced EMF, $\epsilon=0.0143\ volts$

Explanation:

Given that,

Radius of the circular loop, r = 5 cm = 0.05 m

Time, t = 0.0548 s

Initial magnetic field, $B_i=200\ mT=0.2\ T$

Final magnetic field, $B_f=300\ mT=0.3\ T$

The expression for the induced emf is given by :

$\epsilon=\dfrac{d\phi}{dt}$

$\phi$ = magnetic flux

$\epsilon=\dfrac{d(BA)}{dt}$

$\epsilon=A\dfrac{d(B)}{dt}$

$\epsilon=A\dfrac{B_f-B_i}{t}$

$\epsilon=\pi (0.05)^2\times \dfrac{0.3-0.2}{0.0548}$

$\epsilon=0.0143\ volts$

So, the induced emf in the loop is 0.0143 volts. Hence, this is the required solution.

5 0

3 years ago