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DerKrebs [107]
3 years ago
11

A camera rests on a platform that is 10 meters above the ground. what kind of energy does it possess?

Physics
2 answers:
Delvig [45]3 years ago
8 0

Answer:

this is gravitational potential energy that is stored in that position of camera

Explanation:

As we know that the camera is at height 10 m from the ground

h = 10 m

also we know that camera is at the position of 10 m from the ground at rest position

So here we can say that kinetic energy of the camera is ZERO

so here the energy is possessed due to the position of the camera and it is the gravitational potential energy that is stored in it

So here the energy is given as

U = mgH

so this is gravitational potential energy that is stored in that position of camera

victus00 [196]3 years ago
7 0
Is the camera moving?
Nope, it's at rest.
No kinetic energy there.

Is it at some distance above ground?
Yepp, height of 10m.
You've got gravitational potential energy!

To calculate it you'll use the equation:

energy = mgh
... if you want to. ;)
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4 years ago
Can someone help with physics
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50m/s, 187.5m

Explanation:

Consider unit analysis:

m/s² = m/(s×s)

This can be read as "meters per second, per second". From fundamental kinematics, meters per second is the same as saying velocity.

Velocity is being increased per second, and this is called acceleration:

a = v/t, where a is acceleration, v is change of velocity and t is change of time. "Change" is represented by a triangle called delta and (delta)A = A2 - A1

From the question, we have the variables:

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The final velocity of the vehicle is 50m/s.

A formula exists to find displacement with regards to acceleration:

d=v(initial) × t +1/2 × a × t²

d=25m/s × 5s + 1/2 × 5m/s² ×(5s)²

d=125m+1/2×125m

d=125m+62.5m

d=187.5m

The distance travelled by the vehicle is 192.5m.

<em>One of the most important skills you can have in any science is unit analysis. Treat meters, seconds, moles, etc as </em><em>values</em><em> when doing </em><em>calculations</em><em> </em><em>and see if you get the result you're looking for.</em>

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Images formed by a convex mirror are always ​
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Images formed by a convex mirror are always ​virtual

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<u>OAmalOHopeO</u>

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3 years ago
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