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3 years ago

When balancing an equation, should you adjust the subscripts or the coefficients?

Chemistry

2 answers:

ikadub [295]3 years ago

5 0

Answer:

The coefficients.

Explanation:

If you change the subscripts you are changing the chemical formulae.

dimulka [17.4K]3 years ago

3 0

Coefficients, you can’t change the subscripts but you can balance the equation by adding coefficients to both sides

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How many liters of h2 gas, collected over water at an atmospheric pressure of 752 mm hg and a temperature of 21.0°c, can be made

natta225 [31]

Answer:
The balanced equation tells us that 1 mole of Zn will produce 1 mole of H2.
1.566 g Zn x (1 mole Zn / 65.38 g Zn) = 0.02395 moles Zn
0.02395 moles Zn x (1 mole H2 / 1 mole Zn) = 0.02395 moles H2 produced
Now use the ideal gas law to find the volume V.
P = 733 mmHg x (1 atm / 760 atm) = 0.964 atm
T = 21 C + 273 = 294 K
PV = nRT
V = nRT/ P = (0.02395 moles H2)(0.0821 L atm / K mole)(294 K) / (0.964 atm) = 0.600 L

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3 years ago

2Mg + O2à MgO For this unbalanced chemical equation, what is the coefficient for oxygen when the equation is balanced? A. 1 B. 2

Vikki [24]

Answer:

The answer to your question is the letter A. 1

Explanation:

Unbalanced chemical reaction

Mg + O₂ ⇒ MgO

Reactants Elements Products

1 Magnesium 1

2 Oxygen 1

Balanced chemical reaction

2Mg + O₂ ⇒ 2MgO

Reactants Elements Products

2 Magnesium 2

2 Oxygen 2

Conclusion

The coefficients of the balanced equation are 2, 1, 2

7 0

2 years ago

Read 2 more answers

What is the area of triangle ABC with vertices A(x¹,y¹), B(x²,y²)and C (x³,y³)??????????<br>

AlexFokin [52]

Answer:

$Area = \frac{1}{2}|x_1(y_2 - y_3)+x_2(y_3 - y_1)+x_3(y_1 - y_2)|$

$Area = 2\ units^2$

Explanation:

Given

$A = (x_1,y_1)$

$B = (x_2,y_2)$

$C = (x_3,y_3)$

Required

Determine the area

The area of a triangle is :

$Area = \frac{1}{2}|A_x(B_y - C_y) + B_x(C_y - A_y) + C_x(A_y - B_y)|$

By substituting values for the x and y coordinates of A, B and C;

We have:

$Area = \frac{1}{2}|x_1(y_2 - y_3)+x_2(y_3 - y_1)+x_3(y_1 - y_2)|$

So:

For instance

$A = (0,3)$

$B= (2,1)$

$C = (2,3)$

The area is:

$Area = \frac{1}{2}|0(1-3) + 2(3-3) + 2(3-1)|$

$Area = \frac{1}{2}| 2*0 + 2*2|$

$Area = \frac{1}{2}| 0 + 4|$

$Area = \frac{1}{2}|4|$

$Area = \frac{1}{2} * 4$

$Area = 2\ units^2$

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2 years ago

Scientist name: ______________

nikitadnepr [17]

This is easy… like you can’t take 20 min to search this up in Googl

5 0

2 years ago

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When dipentyl ether is treated with HI, what type of reaction occurs? both SN1 and SN2 SN2 E1 SN1 E2

masha68 [24]

Answer:

SN2

Explanation:

The first step of ether cleavage is the protonation of the ether since ROH is a better leaving group than RO-.

The second step of the reaction may proceed by either SN1 or SN2 mechanism depending on the structure of the ether. Methyl and primary ethers react with HI by SN2 mechanism while tertiary ethers react with HI by SN1 mechanism. Secondary ethers react with HI by a mixture of both mechanisms.

Dipentyl ether is a primary ether hence when treated with HI, the reaction with HI proceeds by SN2 mechanism as explained above.

7 0

3 years ago