Answer:
C
Explanation:
I just aswered this question and i got it right
Given:
12.0 M HCl
2.0 liters of a 3.0 M HCl
Required:
volume of concentrated hydrochloric acid
Solution:
M1V1 = M2V2
(12.0 M HCl)V1 = (3.0 M HCl)( 2.0 liters)
V1 = (3.0 M HCl)( 2.0 liters)/ (12.0
M HCl)
V1 = 0.5 liters
Answer:
K = 6.5 × 10⁻⁶
Explanation:
C₅H₆O₃ ⇄ C₂H₆ + 3CO
Use PV=nRT to find the initial pressure of C₅H₆O₃
P (2.50) = (0.0493) (0.08206) (473)
P = 0.78atm
C₅H₆O₃ ⇄ C₂H₆ + 3CO
0.78atm 0 0
0.78 - x x 3x
1.63atm = 0.78 - x + x + 3x
P(total) = 0.288atm
C₅H₆O₃ = 0.78 - 0.288
= 0.489atm
C₂H₆ = 0.288atm
CO = 0.846atm
= 0.379
= 6.5 × 10⁻⁶
B A C ( Blood Alcohol Content ) of 0.10 means that there are 0.10 g of alcohol for every dl of blood.
5 L = 50 dl
50 * 0.10 g = 5 g
In his blood is circulating 5 grams of alcohol.
We can get the mass of the lead metal by calculating the difference between the Mass of evaporating dish and lead metal and the mass of empty evaporating dish. The mass of lead metal is 1.9627 grams. The mass of sulfide is obtained by calculating the difference between Mass of evaporating dish and lead sulfide and the mass of evaporating dish and lead metal. The mass of sulfur added is 0.558 grams. We convert masses to moles. Lead is 0.0093 moles while sulfur is 0.017 moles. We divide each with the less amount between the two. Hence, lead is 1 an sulfur 1.83 or 2. The formula is PbS2 or lead (IV) sulfide.